Interview Questions.

Q1. A Bag Contains 6 Black And eight White Balls. One Ball Is Drawn At Random. What Is The Probability That The Ball Drawn Is White?

Let quantity of balls = (6 + eight) = 14.

Number of white balls = 8.

P (drawing a white ball) =8/14=4/7.

Q2. If Shalu Buys 6 More Apples, His Carton Will Weigh 14.Five Kilograms.If The Weight Of One Apple Is 250 Grams.How Many Apples Did He Initially Had In His Carton?

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Weight of 1 apple = 250 g

Weight of 6 apples = 250 * 6= 1.5 kg

Initial weight = 14.5 – 1.5= 13 kg

Number of apples in his carton initially :

= 13000/250

=52 apples

Q3. It Takes Eight Hours For A 600 Km Journey, If 120 Km Is Done By Train And The Rest By Car. It Takes 20 Minutes More, If 200 Km Is Done By Train And The Rest By Car. The Ratio Of The Speed Of The Train

Let the speed of the train be x km/hr and that of the car be y km/hr. 

Then,120/x+480/y= 8  -> 1/x+4/y =1/15...(1)

And,200/x+400/y=25/3-> 1/x+2/y =1/24....(2)

fixing(1)and(2)we get: x = 60 and y = 80.

Ratio of speeds=60:80=three:four.

Q4. Two, Trains, One From Howrah To Patna And The Other From Patna To Howrah, Start Simultaneously. After They Meet, The Trains Reach Their Destinations After 9 Hours And 16 Hours Respectively. The Ratio

Let us call the trains as A and B. Then,

(A's velocity) : (B's speed) = b : a = 16 : nine = four : 3.

Q5. Tickets Numbered 1 To 20 Are Mixed Up And Then A Ticket Is Drawn At Random. What Is The Probability That The Ticket Drawn Has A Number Which Is A Multiple Of 3 Or 5?

Here, S = 1, 2, 3, 4, ...., 19, 20.

Let E = occasion of having a a couple of of three or five = 3, 6 , 9, 12, 15, 18, 5, 10, 20.

P(E) =   n(E)/ n(S)=nine/20.

Q6. The Average Of The First 100 Positive Integers Is?

N(n+1)/2

1+2+3+....+n

therefore average of these numbers=n+1/2

therefore required common

one hundred+half of=50.5

Q7. There Are Two Examinations Rooms A And B. If 10 Students Are Sent From A To B, Then The Number Of Students In Each Room Is The Same. If 20 Candidates Are Sent From B To A, Then The Number Of Students

Let the quantity of college students in rooms A and B be x and y respectively.

Then, x - 10 = y + 10      x - y = 20 .... (i)

and x + 20 = 2(y - 20)      x - 2y = -60 .... (ii)

Solving (i) and (ii) we get: x = one hundred , y = eighty.

The required solution A = one hundred.

Q8. Present Ages Of Sameer And Anand Are In The Ratio Of 5 : four Respectively. Three Years Hence, The Ratio Of Their Ages Will Become 11 : nine Respectively. What Is Anand's Present Age In Years?

Let the present a while of Sameer and Anand be 5x years and 4x years respectively.

Then, 5x + 3/4x + 3=eleven/9

         9(5x + three) = eleven(4x + 3)

         45x + 27 = 44x + 33

         45x - 44x = 33 - 27

         x = 6.

        Anand's present age = 4x = 24 years.

Q9. A Bike Runs At The Speed Of 50 Km/h When Not Serviced And Runs At 60 Km/h When Serviced. After Servicing The Bike Covers A Certain Distance In 6 H. How Much Time Will The Car Take To Cover The Same Di

From the given statistics, after servicing velocity of the motorcycle = 60 km/h

Distance covered in 6h. = (60 * 6) km = 360km

When it’s no longer provider,the time taken to cowl 360 km = (360 / 50) = 7.2h

Q10. The Sum Of The Present Ages Of A Father And His Son Is 60 Years. Six Years Ago, Father's Age Was Five Times The Age Of The Son. After 6 Years, Son's Age Will Be?

Let the existing a long time of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

 54 - x = 5x - 30

 6x = eighty four

 x = 14.

Son's age after 6 years = (x+ 6) = 20 years..

Q11. A Tailor Has 37.5 Metres Of Cloth And He Has To Make eight Piecesout Of A Metre Of Cloth. How Many Pieces Can He Make Out Of This Cloth?

The tailor has to make 8 piece from 1 metre.

So for 1 piece ,the dimension might be 1/8=0.125 m

from 37.Five m tailor can get 37.Five/0.125 = three hundred pieces

Q12. In A Flight Of 600 Km, An Aircraft Was Slowed Down Due To Bad Weather. Its Average Speed For The Trip Was Reduced By 2 hundred Km/hr And The Time Of Flight Increased By 30 Minutes. The Duration Of The Fligh

Let the duration of the flight be x hours.

Then,six hundred/x-six hundred/x + (1/2)= two hundred

600/x-1200/2x + 1= 200

x(2x + 1) = three

2x2 + x - three = zero

(2x + 3)(x - 1) = 0

x= 1 hr. 

Q13. A Man Covered A Certain Distance At Some Speed. Had He Moved 3 Kmph Faster, He Would Have Taken 40 Minutes Less. If He Had Moved 2 Kmph Slower, He Would Have Taken forty Minutes More. The Distance (in Km

Let distance = x km and standard charge = y kmph.

Then,x/y-x/y+3=forty/60 -> 2y(y + three) = 9x ....(i)     

And,x/y -2-x/y=40/60 -> y(y - 2) = 3x ....(ii)

On dividing (i) via (ii), we get: x = 40.

Q14. Six Years Ago, The Ratio Of The Ages Of Kunal And Sagar Was 6 :

Let the a while of Kunal and Sagar 6 years ago be 6x and 5x years respectively.

Then, (6x + 6) + four/(5x + 6) + 4  =11/10

          10(6x + 10) = 11(5x + 10)

          5x = 10     

          x = 2.

Sagar's present age = (5x + 6) = 16 years.

Q15. A Man Is 24 Years Older Than His Son. In Two Years, His Age Will Be Twice The Age Of His Son. The Present Age Of His Son Is?

Let the son's gift age be x years. Then, guy's gift age = (x + 24) years.

 (x + 24) + 2 = 2(x + 2)

 x + 26 = 2x + four

 x = 22.

Q16. What Are The Average Marks Obtained By All The Seven Students In Physics?

Average marks received in Physics by way of all the seven students

=1/7x [ (90% of 120) + (80% of 120) + (70% of 120) + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120) ]

=1/7x [ (90 + 80 + 70 + 80 + 85 + 65 + 50)% of 120 ]

=1/7x [ 520% of 120 ]

=624/7

= 89.14.

Q17. A Farmer Travelled A Distance Of 61 Km In 9 Hours. He Travelled Partly On Foot

Let the gap travelled walking be x km.

Then, distance travelled on bicycle=(61 -x)km.

So,x/four+(61 -x)/9= 9

9x + four(61 -x) = nine x 36

5x = 80

x = sixteen km.

Q18. What Is The Probability Of Getting A Sum nine From Two Throws Of A Dice?

In  throws of a dice, n(S) = (6 x 6) = 36.

Let E = occasion of having a sum =(3, 6), (4, 5), (five, 4), (6, 3).

P(E) =   n(E)/ n(S)=4/36 =1/9.

Q19. What Was The Aggregate Of Marks Obtained By Sajal In All The Six Subjects?

Aggregate marks obtained by using Sajal

= [ (90% of 150) + (60% of 130) + (70% of 120) + (70% of 100) + (90% of 60) + (70% of 40) ]

= [ 135 + 78 + 84 + 70 + 54 + 28 ]

= 449.

Q20. If The Graphs Of The Equations X + Y = zero And 5y + 7x = 24 Intersect At (m, N), Then The Value Of M +n Is?

By fixing the given  equations, we get the intersection factor (12, - 12).

So, m = 12, n = -12

Hence, m + n = 12 – 12 = 0.

Q21. The Average Score Of A Cricketer For 13 Matches Is forty two Runs. If His Average Score For The First 5 Matches Is 54, Then What Was His Average Score (in Runs) For Last 8 Matches?

Total Score = Average * Number of fits

Total score of 13 suits = 13 × forty two = 546

Total rating of first 5 matches = five × fifty four = 270

Therefore, overall rating of final 8 matches = 546 - 270 = 276

Average = 276/eight = 34.5

Q22. What Annual Payment Will Discharge A Debt Of Rs. 6,450 Due In 4 Years At 5% Per Annum Simple Interest?

Let the annual installment be rs. X

consequently (x + x*3*five/one hundred)+(x + x*2*five/one hundred)

+(x + x*1*5/a hundred)+x =6450

=>115x/a hundred+110x/one hundred+105x/a hundred+x=6450

=>115x+110x+105x+100x=6450*one hundred

=>430x=6450*one hundred

x=6450*a hundred/430=rs.1500

Q23. How Many Digits Will Be There To The Right Of The Decimal Point In The Product Of ninety five.Seventy five And .02554 ?

Sum of decimal locations = 7.

Since the remaining digit to the acute proper could be 0 (due to the fact 5 x four = 20),

so there may be 6 considerable digits to the right of the decimal point.

Q24. What Is The Average Candidates Who Appeared From State Q During The Given Years?

Required common=8100 + 9500 + 8700 + 9700 + 8950/5

=44950/5

= 8990.

Q25. If A Person Walks At 14 Km/hr Instead Of 10 Km/hr, He Would Have Walked 20 Km More. The Actual Distance Travelled By Him Is?

Let the real distance travelled be x km.

Then, x/10=x + 20/14

14x = 10x + 200

4x = 200

x= 50 km.

Q26. Robert Is Travelling On His Cycle And Has Calculated To Reach Point A At 2 P.M. If He Travels At 10 Kmph, He Will Reach There At 12 Noon If He Travels At 15 Kmph. At What Speed Must He Travel To Reach

Let the distance travelled by way of x km.

Then,x/10-x/15= 2

 3x - 2x = 60

 x = 60 km.

Time taken to journey 60 km at 10 km/hr =[60/10]hrs= 6 hrs.

So, Robert commenced 6 hours earlier than 2 P.M. I.E., at eight A.M.

Required pace =[60/5]kmph.= 12 kmph.

Q27. A Man Has Some Hens And Cows. If The Number Of Heads Be 48 And The Number Of Feet Equals a hundred and forty, Then The Number Of Hens Will Be?

Let the quantity of hens be x and the range of cows be y.

Then, x + y = forty eight .... (i)

and 2x + 4y = 140      x + 2y = 70 .... (ii)

Solving (i) and (ii) we get: x = 26, y = 22.

The required answer = 26.

Q28. The Diameter Of A Circle Is 21 Metres. It Will Take How Many Revolutions To Cover A Distance Of 6.6 Km?

No. Of revolutions = Distance/circumference.

Distance = 6.6 × one thousand = 6600 metres.

Circumference = 2 × 22/7 × 21/2 = 66 metres.

No. Of revolutions = 6600/66 = 100 revolutions.

Q29. In Covering A Distance Of 30 Km, Abhay Takes 2 Hours More Than Sameer. If Abhay Doubles His Speed, Then He Would Take 1 Hour Less Than Sameer. Abhay's Speed Is?

Let Abhay's pace be x km/hr.

Then,30/x-30/2x= three

 6x = 30

 x = five km/hr.

Q30. The Length And Breadth Of A Rectangle Are Increased By 20% And forty% Respectively. What Is The Percentage Increase In Its Area?

Apply the percentage components.

The percent increase within the place could be P + Q + PQ / 100.

So we get the solution as 20 +forty + 20 × 40/a hundred = sixty eight%. 

Q31. In A Family, The Average Age Of A Father And A Mother Is 35 Years. The Average Age Of The Father, Mother And Their Only Son Is 27 Years. What Is The Age Of The Son?

Father+Mother=2*35=70 years

Father+Mother+Son=27*three=eighty one years

therefore Son's age=81-70=eleven years