Top 100+ Yahoo Aptitude Interview Questions And Answers
Question 1. What number of Children Did Not Try Any Of The Rides. ?
Answer :
20 children * 3 rides = Rs. 60
(55-20=)35 children * 2 rides = Rs. 70
60 + 70 = Rs. 130
In this way, Rs. (145 – 130 = ) 15 are left for the other (85 – 55 = ) 30 children .
so just 15 of them can take a ride and rest 15 will be forgotten about.
145 rides were taken.
20 of them took each of the three,
for example Rs. 60 were spent, so 145-60= Rs. 85 are left for the others.
Absolute children were 85, so rest were 65. out of these 65.
Question 2. Six Bells Commence Tolling Together And Toll At Intervals Of 2, 4, 6, 8 10 And 12 Seconds Respectively. In 30 Minutes, How Many Times Do They Toll Together ?
Answer :
L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
Along these lines, the chimes will cost together after each 120 seconds(2 minutes).
In a short time, they will cost together 30/2+ 1 = multiple times.
Inclination Interview Questions
Question 3. Take a gander At This Series: 2, 1, (1/2), (1/4), ... What Number Should Come Next?
Answer :
This is a straightforward division arrangement; each number is one-portion of the past number. In different terms to state, the number is partitioned by 2 progressively to get the following outcome.
4/2 = 2
2/2 = 1
1/2 = 1/2
(1/2)/2 = 1/4
(1/4)/2 = 1/8, etc.
Question 4. On the off chance that G (0)=g (1)=1 And G (n)= G (n-1) + G (n - 2) Find G (6)?
Answer :
G(0) = 1
G(1) = 1
G(2) = G(1) + g(0) = 2
G(3) = g(2) + g(1) = 3
G(4) = g(3) + g(2) = 5
G(5) = g(4) + g(3) = 8
G(6) = g(5) +g (4) = 13
Question 5. A Person Travels 48 Kms At 12 Kms/hour And Further 48 Kms At 16km.s/hour. His Average Speed For The Whole?
Answer :
Speed = (Total Distance/Total Time)
TD = 48 + 48= 96,
T1 = 48/12 = 4hrs
T2 = 48/16 = 3hrs
T1 + T2 = 4 + 3 = 7
Avg Speed = 96/7 = 13(5/7) km/hr
Wipro Aptitude Interview Questions
Question 6. What number of Numbers Between 1 And 100 Are Divisible By 7 ?
Answer :
No. of distinguishable by 7, 14 - 98, n = a + (N - 1)d
98 = 7 + (N - 1) 7, 98 = 7 + 7N – 7
98/7= N = 14
Question 7. A Reduction Of 20% In The Price Of Mangoes Enables A Person To Purchase 12 More For Rs. 15. What Was The Price Of 16 Mangoes Before Reduction Of Price ?
Answer :
Value x Consumption = Expenditure
Utilization = Exp. Cost
(15/8x) - (15/x) = 12
x = (15 x 2)/(12 x 8)
For 16 Mangoes = [(15 x 2)/(12 x 8)] x 16 = 5
ABB Group Aptitude Interview Questions
Question 8. A Sum Of Money Is To Be Distributed Among A, B, C, D In The Proportion Of 5 : 2 : 4 : 3. On the off chance that C Gets Rs. 1000 More Than D, What Is B's Share?
Answer :
Let the portions of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x separately.
At that point, 4x - 3x = 1000
x = 1000.
B's offer = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
Question 9. It Was Sunday On Jan 1, 2006. What Was The Day Of The Week Jan 1, 2010?
Answer :
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Along these lines, on first Jan, 2010 it is Friday.
VMware Aptitude Interview Questions
Question 10. What Was The Day Of The Week On 28th May, 2006?
Answer :
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 common years + 1 jump year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. Walk April May
(31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
All out number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Question 11. Today Is Monday. Following 61 Days, It Will Be?
Answer :
Every day of the week is rehashed following 7 days.
In this way, following 63 days, it will be Monday.
Following 61 days, it will be Saturday.
Worth Labs Aptitude Interview Questions
Question 12. On eighth Dec, 2007 Saturday Falls. What Day Of The Week Was It On eighth Dec, 2006?
Answer :
The year 2006 is a customary year. In this way, it has 1 odd day.
Along these lines, the day on eighth Dec, 2007 will be 1 day past the day on eighth Dec, 2006.
Be that as it may, eighth Dec, 2007 is Saturday.
eighth Dec, 2006 is Friday.
Bent Interview Questions
Question 13. What Least Number Must Be Added To 1056, So That The Sum Is Completely Divisible By 23 ?
Answer :
In the event that the number 1056 is totally distinguishable by 23 methods, leftover portion should come zero.
Be that as it may, on the off chance that we partition 1056 by 23, the rest of 2.
So if 2 is added to the 1056, we get leftover portion 0.
In this manner arrangement is 2.
Question 14. The Largest 4 Digit Number Exactly Divisible By 88 Is?
Answer :
Separation biggest four digit number 9999 by 88. You get 113.625.
Clearly 113 would be actually distinguishable so we need to realize what that number is.
We get this by increasing 113 with 88 = 9944
Question 15. The Difference Of Two Numbers Is 1365. On Dividing The Larger Number By The Smaller, We Get 6 As Quotient And The 15 As Remainder. What Is The Smaller Number ?
Answer :
Leave the more modest number alone x. At that point bigger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
More modest number = 270.
Abaxis Aptitude Interview Questions
Question 16. A Sum Of Money At Simple Interest Amounts To Rs. 815 In 3 Years And To Rs. 854 In 4 Years. The Sum Is?
Answer :
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for a long time = Rs.(39 x 3) = Rs. 117.
Head = Rs. (815 - 117) = Rs. 698.
Question 17. A Father Said To His Son, "I Was As Old As You Are At The Present At The Time Of Your Birth". On the off chance that The Father's Age Is 38 Years Now, The Son's Age Five Years Back Was?
Answer :
Let the child's current age be x years. At that point, (38 - x) = x
2x = 38.
x = 19.
Child's age 5 years back (19 - 5) = 14 years.
Question 18. An Is Two Years Older Than B Who Is Twice As Old As C. In the event that The Total Of The Ages Of A, B And C Be 27, The How Old Is B?
Answer :
Leave C's age alone x years. At that point, B's age = 2x years. An's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Consequently, B's age = 2x = 10 years.
Wipro Aptitude Interview Questions
Question 19. Two Trains Running In Opposite Directions Cross A Man Standing On The Platform In 27 Seconds And 17 Seconds Respectively And They Cross Each Other In 23 Seconds. The Ratio Of Their Speeds Is?
Answer :
Leave the velocities of the two trains alone x m/sec and y m/sec separately.
At that point, length of the primary train = 27x meters,
what's more, length of the second train = 17y meters.
27x + 17y/x+ y = 23
27x + 17y = 23x + 23y
4x = 6y
x/y=3/2.
Question 20. A Train Speeds Past A Pole In 15 Seconds And A Platform 100 M Long In 25 Seconds. Its Length Is?
Answer :
Leave the length of the train alone x meters and its speed by y m/sec.
At that point, x/y= 15 => y =x/15 .
Hence x + 100/25=x/15.
=> 15(x + 100) = 25x
=> 15x + 1500 = 25x
=> 1500 = 10x
=> x = 150 m.
Question 21. A Rectangular Tract Of Land Measures 860 Feet By 560 Feet. Around How Many Acres Is This? (one Acre = 43,560 Square Feet)?
Answer :
Territory of the rectangular tract = Length x Breadth = 860 x 560 Sq.ft. = {860x560}/43560 sections of land = 11.06 sections of land.
Question 22. Three Unbiased Coins Are Tossed. What Is The Probability Of Getting At Most Two Heads?
Answer :
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = occasion of getting all things considered two heads.
At that point E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E) = n(E)/n(S)=7/8.
Question 23. Two Dice Are Thrown Simultaneously. What Is The Probability Of Getting Two Numbers Whose Product Is Even?
Answer :
In a synchronous toss of two shakers, we have n(S) = (6 x 6) = 36.
At that point, E = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4),
(3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),
(6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
n(E) = 27.
P(E) = n(E)/n(S)=27/36=3/4.
Question 24. A Card Is Drawn From A Pack Of 52 Cards. The Probability Of Getting A Queen Of Club Or A King Of Heart Is?
Answer :
Here, n(S) = 52.
Let E = occasion of getting a sovereign of club or a lord of heart.
At that point, n(E) = 2.
P(E) =n(E)/n(S)=2/52=1/26.
ABB Group Aptitude Interview Questions
Question 25. What Is The Overall Percentage Of Tarun?
Answer :
Total imprints got by Tarun
= [ (65% of 150) + (35% of 130) + (half of 120)
+ ((77% of 100) + (80% of 60) + (80% of 40) ]
= [ 97.5 + 45.5 + 60 + 77 + 48 + 32 ]
= 360.
The most extreme signs (of all the six subjects)
= (150 + 130 + 120 + 100 + 60 + 40)
= 600.
Consequently Overall level of Tarun =(360/600x 100)% = 60%.
Question 26. A Man Has Rs. 480 In The Denominations Of One-rupee Notes, Five-rupee Notes And Ten-rupee Notes. The Number Of Notes Of Each Denomination Is Equal. What Is The Total Number Of Notes That He Has ?
Answer :
Leave number of notes of every category alone x.
At that point x + 5x + 10x = 480
16x = 480
x = 30.
Consequently, absolute number of notes = 3x = 90.
