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Top 100+ Wipro Aptitude Interview Questions And Answers - May 25, 2020

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Top 100+ Wipro Aptitude Interview Questions And Answers

Question 1. Nine Laboures Can Complete The Construction Of A Wall In 18 Days. How Many Less Days Will 12 Laboures Take To Complete The Same Wall?

Answer :

Work finished with the aid of a unmarried man or woman = 1/ ( nine* 18) = 1/ 162

Work achieved via 12 humans = 12 / 162

Time taken to complete paintings = 162 / 12 = 13.5

Question 2. The Rectangle Box With Square Base Is Open At The Top. The Maximum Volume Of The Box Made From 1200 M2 Tin,in M3 Is?

Answer :

Let the period be x and the breadth be y.

Now because it has a square base;

x=y

Now the floor place may be given as S= x^2+4xy (Area of rectangular base + Area of Sides)

And Volume may be given as V = x^2y

ATQ, S=1200,so 1200=X2+4xy

y=(1200-x2)/4x

Now for V to be max

V'=zero

V'(x)=x2y

Solving for x we get x=20

Now y=20m

Hence volume is 20x20x10=4000 m3

Wipro Technical Interview Questions
Question three. A Person Was Fined For Exceeding The Speed Limit By 10 Km/hr. Another Person Was Also Fined For Exceeding The Same Speed Limit By Twice The Same. If The Second Person Was Traveling At A Speed Of 35km/hr,discover The Speed Limit?

Answer :

1 person surpassed with the aid of 10. Another person twice 10 that is 20. Given he goes at 35 km/h. So velocity limit is 35 - 20=15 km/hr

Question four. The Difference Between The Compound And Simple Interest On A Certain Sum For 2 Years At The Rate Of eight% Per Annum Is Rs.80,what Is The Sum?

Answer :

Since we recognise that SI and CI are equal for first year. Difference is due to the SI of 1st yr is dealt with as PRINCIPLE of 2nd year in CI.

So 1st we calculate the quantity which treated as P in CI

P = 100*SI/R*T = a hundred*eighty/eight*1 = a thousand

This amount is likewise the SI for 1 12 months.

So

SI = 1000

T = 1 Year

R = 8%

P = 100*one thousand/eight*1 = 12500

Question five. The Ratio Between Two Numbers Is five:7 And Their Product Is 560. What Is The Difference Between These Two Numbers?

Answer :

From the above information

x/y = 5/7

xy = 560

Solving the above equation we get the numbers as 20 and 28

Difference is eight

Wipro Java Interview Questions
Question 6. The Mean And The Variance Of A Binomial Distribution Are 4 And 2 Respectively. Then The Probability Of 2 Successes Is?

Answer :

Given that variance npq = 2

and imply np = 4

q = half of

=> p = 1/2

n = 8

=> 8c2 * (half)^eight = 28/256

ans = 28/256

Question 7. Take Any Positive Whole Number Not Greater Than 50.If The Number Is Even, Divide It By 2.If The Number Is Odd,multiply It By three,and Add 1 To The?

Answer :

result. Apply the equal method to the resulting numbers till you ultimately arrive on the #1.Proven beneath is the chain of numbers that results from

this method in case you begin with 15.

15->forty six->23->70->35->106->fifty three->160->80->40->20->10->five->16->8->four->2->1

TCS HR Interview Questions
Question 8. As You Can See, The Number 15 Requires 17 Steps To End Up At 1.Of The Numbers Not Greater Than 50,which Takes The Longest To Reach The Number 1 ?

Answer :

27, which takes 111 steps

Question 9. After Spending 2/three Of His Salary On Rent And Food Items And 1/4th Of The Remaining On Transportation, Rajesh Has 6000 With Him. How Much Did He Pay On Transportation?

Answer :

Let x be the profits.

Then if he spends (2/three)x on lease and meals then the final income is x/three,

Out of which he spends 1/4 i.E(x/three)1/four or x/12 on transportation...And the amount left thereafter is : ( x/3 ) - ( x/12 ) = x/4

Given..The quantity left with Rajesh is : 6000 = x/4

=> Salary of Rajesh 'x' is : 6000 * four = Rs.24,000

Amount spent on lease and food = 24000 * (2/3) = Rs.16,000

Remaining quantity : 24000 - 16000 = Rs.8000

Amount spent on transportation : 8000 * (1/four) = Rs.2000

Remaining amount : 8000 - 2000 = Rs.6000,the amount left with Rajesh

So answer is : 2000

ABB Group Aptitude Interview Questions
Question 10. E=i*i*r What Is The Effect Of E When I Becomes I/2?

Answer :

E = I * I * R

Now if I = I / 2

Now E = I/2 * I/2 * R

Therefore E will decrease four instances

Question 11. Out Of 55 Eggs five Are Defective. What Is % Of Defective Eggs?

Answer :

(five/55)*one hundred = 9 1/11

VMware Aptitude Interview Questions
Question 12. Salary Of A Person Is 's' Per Month,'x'% Of Salary Is Given As Bonus, If 3 Months Salary Is S1,s2 & S3 Then What Is His Salary?

Answer :

s1*x/a hundred + s2*x/one hundred + s3*x/one hundred 

s1 = s2 = s3

Ans = s1*x/100

Wipro Technical Interview Questions
Question 13. In Base 10 Representation For A Rupee a hundred Paise,then Base eight Representation What Is Rupee Value?

Answer :

Octal representation of decimal one hundred is one hundred forty four

10010 = 1448

Question 14. A Sum 's' Is Divided Into 4 Parts. Second Person Gets Rs 10 More Than First.Third Person Is Rs 10 More Than Second, 4th Is 10 More Than 3rd. How Much Amount Do 1st Person Get.?

Answer :

1st person receives Rs.(s-60)/4

Let us assume that 1st character receives Rs.X

Then 2d will get Rs.X+10

3rd will get Rs.X+20

4th will get Rs.X+30

Then the sum s=x+(x+10)+(x+20)+(x+30)

=> s=4x+60

=> 4x=s-60

=> x=(s-60)/4

Therefore 1st pesron gets (s-60)/four

Question 15. 1/8 Is Divided By 's' , If 's' Is Increased By 2 Times, What Is The Result?

Answer :

Answer = 1/(8s/2)

= 1/4s

Increases two instances

Value Labs Aptitude Interview Questions
Question 16. X Y Z U V W R S T __?

Answer :

Divide the series into letters of 3. One series starts offevolved with next letter of the last character in 2d collection. 

X y z u v w r s t o

Question 17. A C F J O __

Answer :

ExplanationDiscuss the answer:

Difference between letter index position increases as 1, 2, 3, 4, 5...

Answer is u.

Abaxis Aptitude Interview Questions
Question 18. Mr. Shah Decided To Walk Down The Escalator Of A Tube Station. He Found That If He Walks Down 26 Steps, He Requires 30 Seconds To Reach The Bottom.?

Answer :

In 12 sec(30-18) he walks down eight(34-26) steps.

Consequently, (eight*30)/12 =20 steps.

So,the total height of the stair way in steps=(26+20)=46 steps

Wipro Java Interview Questions
Question 19. The Average Age Of 10 Members Of A Committee Is The Same As It Was four Years Ago, Because An Old Member Has Been Replaced By A Young Member.Discover How Much Younger Is The New Member ?

Answer :

Let the contributors be Old Having age O + different nine having a long time x and New one having age Y

Sum of their ages = (Y + 9 × x) and average = (Y + 9 × x)/10

Before 4 years sum changed into (O + nine x – 10 × 4) and average = (O + 9 x – 10 × 4) /10

equating, Y + nine x = O + 9x – forty

Y = O – 40

Younger is 40 years more youthful than Old one.

Question 20. Abce Is An Isosceles Trapezoid And Acde Is A Rectangle. Ab = 10 And Ec = 20. What Is The Length Of Ae?

Answer :

From factor A we draw the perpendicular

segment AP to the idea EC.

Then EP=(20-10)/2=five

From the square triangle EAC

(A=90) we've got

(AE)^2=(EP)(EC)

(AE)^2=five*20

(AE)^2=100

(AE)=10

SAP Aptitude Interview Questions
Question 21. Three Containers A, B And C Have Volumes A, B, And C Respectively; And Container A Is Full Of Water While The Other Two Are Empty. If From Container?

Answer :

a , we should subtract

b/three and c/2

so water left in box A

= a - (b/three + c/2)

Question 22. Pa And Pb Are Tangents To The Circle At A And B Respectively And The Chord Bc Is Parallel To Tangent Pa. If Ac = 6 Cm, And Length Of The Tangent Ap Is nine Cm, Then What Is The Length Of The Chord Bc?

Answer :

PA = PB = 9 cm ( Length of tangents from an outside factor) 

Angle PAB = Angle ABC ( change angles PA !! BC)

AC = AB = 6 cm

Triangles PAB and ACB are isosceles and sre comparable triangles

( They are equiangular)

Taking the ratios of respective facets

BC/AB = AC/PB

BC/6 = 6/9

BC = four cm

Question 23. A Number Of Cats Got Together And Decided To Kill Between Them 999919 Mice. Every Cat Killed An Equal Number Of Mice. Each Cat Killed More Mice Than There Were Cats. How Many Cats Do You Think There Were ?

Answer :

Observing the num 999919 which is the entire num of rats being eaten, we will write it as

(1000000-eighty one) = (a thousand^2-nine^2) = (one thousand+nine)(one thousand-nine) = (1009)(991)

So total num of rats killed =(1009)(991)

And given that every cat kills more num of rats than the entire num of cats

Hence each cat kills 1009 num of rats

And there are 991 num of cats

TCS Aptitude Interview Questions
Question 24. If Log2 X - 5 Log X + 6 = zero, Then What Would The Value / Values Of X Be?

Answer :

Log2 x manner (log x)^2,

The answer may be observed by using making the substitution y = log x to present

y^2 - 5y + 6 = zero, which offers the answers

y = 3

y = 2

ie., log x = 2 or log x = three

ie., e2 or e3

TCS HR Interview Questions
Question 25. The Square Of A Two Digit Number Is Divided By Half The Number. After 36 Is Added To The Quotient, This Sum Is Then Divided By 2. The Digits Of The Resulting Number Are The Same As Those In The Original Number, But They Are In Reverse Order. The Ten's Place Of The Original Number Is Equal To Twice The Difference Between Its Digits. What Is The Number?

Answer :

Let the number be 10A + B = C

now, (C^2/(C/2) + 36)/2= 10B + A

or, (2C+36)/2 = 10B + A

or C+18=10B+A

or, 10A + B + 18 = 10 B + A

or, 18=nine(B-A), giving B-A=2

As in step with the question, A=twice the distinction between A and B

Hence A=2*2=4

B=2+4=6

The original number is forty + 6 = 46.

Question 26. Can You Tender A One Rupee Note In Such A Manner That There Shall Be Total 50 Coins But None Of Them Would Be 2 Paise Coins.?

Answer :

In descending order,

the usage of denominations of 1p,5p,10p,25p that are to be had.

Thus,

25p coins : 1

10p cash : 2

5p coins : 2

1p coins : forty five

3i Infotech Interview Questions
Question 27. Complete The Sequence A, E ,i ,m ,q ,u , _ , _?

Answer :

Y,C

After each person +3

ABB Group Aptitude Interview Questions
Question 28. A Person Travels 6km Towards West, Then Travels 5km Towards North ,then Finally Travels 6km Towards West. Where Is He With Respect To His Starting Position?

Answer :

C is the answer, 13 km northwest.

When he traveled first 6km, he's going to b in west.

Then aftr 5km ,he wil b in northwest.

Again he is going to west. So from the given answers, he wil b in north west function.

Question 29. If A Speaks The Truth 80% Of The Times, B Speaks The Truth 60% Of The Times. What Is The Probability That They Tell The Truth At The Same Time?

Answer :

Probability of occasions occurring together = Product of man or woman probabilities

= 0.8 * 0.6 = 0.Forty eight.

Question 30. A Person Travels 12 Km In The Southward Direction And Then Travels 5km To The Right And Then Travels 15km Toward The Right And Finally Travels 5km Towards The East, How Far Is He From His Starting Place?

Answer :

______

three ,7 ,13 ,21 ,31?

Answer :

okay(n) = okay(n-1) +2(n-1) with

k(1) =1

ok(7) =k(6) +2(7-1)

k(7) =31 +2*6

k(7) =31+12

okay(7) =forty three

Question 32. If In A Certain Code "range" Is Coded As 12345 And "random" Is Coded As 123678. Then The Code For The Word "mango" Would Be?

Answer :

M-eight

A-2

N-three

G-4

O-7

So for mango the code is 82347

Question 33. 1st three Letters Are Denoted By Its Next In The Alphabet And The Next three Letters Are Denoted By Its Previous In The Alphabets A Monkey Starts Climbing Up A Tree 20ft. Tall. Each Hour, It Hops 3ft. And Slips Back 2ft. How Much Time Would It Take The Monkey To Reach The Top?

Answer :

The first hour, the monkey is going three toes up, and slips lower back 2 feet.

Zero.1..2..3..Four..Five..6

that is going up instead of horizontal.)

So the monkey is three ft - 2 ft = 1 toes high after one hour.

In the second hour, the monkey is going up three extra toes, and slips returned 2 toes. So he's at 1 feet + three feet - 2 ft = 2 feet.

Every hour, he gains three toes and loses 2 feet, for a total benefit of 1 toes. So after the seventeenth hour, he's at 17 feet excessive.

Now, right here's the twist: inside the 18th hour, he climbs up 3 feet. Since 17 feet + 3 toes = 20 ft, he is on the pinnacle of the tree!

So, it takes him 18 hours.

VMware Aptitude Interview Questions
Question 34. What Is The Missing Number In This Series? 8 2 14 6 11 _ 14 6 18 12?

Answer :

The sum of the primary and last range equal 20

The sum of the second and 2d-to-closing quantity identical 20

The sum of the 1/3 and third-to-ultimate number same 20

So answer is nine

Question 35. A Certain Type Of Mixture Is Prepared By Mixing Brand A At Rs.Nine A Kg. With Brand B At Rs.4 A Kg. If The Mixture Is Worth Rs.7 A Kg., How Many Kgs. Brand A Are Needed To Make 40kgs. Of The Mixture?

Answer :

A + B = 40.

And at Rs 7 a kg for 40 kg, you need a total of Rs.280.

So the second equation is 9A + 4B = 280

From the first equation: B = 40 - A

and sub into the second one equation:

9A + 4(40-A) = 280

9A + 160 - 4A = 280

5A = a hundred and twenty

A = 24.

Your solution, of path, is A = 24.

Question 36. A Wizard Named Nepo Says "i Am Only Three Times My Son's Age. My Father Is 40 Years More Than Twice My Age. Together The Three Of Us Are A Mere 1240 Years Old." How Old Is Nepo?

Answer :

Let the age of nepo be x years,age of his father is (forty+2x),age of his son (x/3)

(40+2x)+x+(x/three)=1240

Solving this equation we get the age of nepo i.E. (x) is 360 years old

Value Labs Aptitude Interview Questions
Question 37. One Dog Tells The Other That There Are Two Dogs In Front Of Me. The Other One Also Shouts That He Too Had Two Behind Him. How Many Are They?

Answer :

dog

dog

dog

So there are three puppies

Question 38. A Man Ate a hundred Bananas In Five Days, Each Day Eating 6 More Than The Previous Day. How Many Bananas Did He Eat On The First Day?

Answer :

Let the variety of bananas in first day be x

For consecutive five days it is going to be like x,x+6,x+12,x+18,x+24

The sum of those are a hundred, 5x+60=100

So,x = eight

Question 39. If It Takes Five Minutes To Boil One Egg, How Long Will It Take To Boil Four Eggs?

Answer :

Five minutes if we keep the four eggs in the identical bowl.

Question 40. The Minute Hand Of A Clock Overtakes The Hour Hand At Intervals Of sixty four Minutes Of Correct Time. How Much A Day Does The Clock Gain Or Lose?

Answer :

Simple clarification by using Juned:

The minute hand overtakes hours hand 11 instances in 12 hours

Therefore the time taken by using the minute to overtake = (12 * 60)/11

                                                                           = 65.4545 mins

In this clock the minute hand is taking sixty four mins to overtake

Therefore in 12 hours it's going to overtake 720/64 = 11.25 instances

That approach 0.25 instances extra in 12 hours or zero.Five instances greater in an afternoon

Hence, the clock profits = zero.5 instances of the normal time

⇒ sixty five.4545 * zero.5 = 32.72 mins or 360/eleven mins

Explanation by means of a4academics

Let

x be distance traveled by using hour hand

Then distance traveled by using minute hand = 1 + x

Time = Distance/Rate

⇒ x/(1/12) = (1 + x)/1

⇒ x = (1/12)(1 + x) = 1/12 + x/12

⇒ (11/12)x = 1/12

x = 1/eleven

Calculate time for minute hand to travel a distance 1 + x.

Time = Distance/Rate

(1 + x)/1 = 1 + x = 1 + 1/11 = 12/11 hour

Actual time to overtake on clock is 64 minutes.

64 min = sixty four/60 hours = sixteen/15 hour

Correct Clock Speed/Actual Clock Speed

(12/11) / (16/15) = 12*15 / (11*sixteen) = 180/176 = forty five/forty four

The clock gains:

45/44 - 1 = 1/44 day = 24/44 hour = 6/eleven hour = 360/11 min

= 32 min and 434/eleven sec.

Abaxis Aptitude Interview Questions




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