Interview Questions.

Question 1. The Average Score Of A Cricketer For 13 Matches Is forty two Runs. If His Average Score For The First 5 Matches Is fifty four, Then What Was His Average Score (in Runs) For Last 8 Matches?

Answer :

Total Score = Average * Number of fits

Total rating of 13 suits = thirteen × 42 = 546

Total score of first 5 matches = 5 × 54 = 270

Therefore, general rating of final 8 fits = 546 - 270 = 276

Average = 276/eight = 34.5

Question 2. If The Graphs Of The Equations X + Y = zero And 5y + 7x = 24 Intersect At (m, N), Then The Value Of M +n Is?

Answer :

By fixing the given  equations, we get the intersection point (12, - 12).

So, m = 12, n = -12

Hence, m + n = 12 – 12 = zero.

SAP BASIS Interview Questions
Question 3. A Function F(x) Is Defined As F(x) = F(x – 2) - X(x + 2) For All The Integer Values Of X And F(1) + F(4) = zero. What Is The Value Of F(1) + F(2) + F(3) + F(4) + F(five) + F(6)?

Answer :

Let S = f(1) + f(2) + f(3) + f(four) + f(5) + f(6)

As f(1) + f(four) = zero, consequently S = f(2) + f(three) + f(five) + f(6) ------ (1)

f(2) = f(0) - 8

f(3) = f(1) - 15

f(4) = f(2) - 24 = f(zero) - 32

f(5) = f(3) - 35 = f(1) - 50

f(6) = f(4) - 48 = f(zero) - 80

Put the above values in equation (1), we get

S = f(0) - eight + f(1) - 15 + f(1) - 50 + f(0) - 80

S = 2(f(zero) + f(1)) - 153 ------ (2)

As we already realize f(1) + f(four) = zero ⇒f(1) + f(0) - 32 = zero ⇒f(1) + f(0) = 32

Putting this cost in equation 2, we get S = 2(32) - 153 = -89

Question 4. What Annual Payment Will Discharge A Debt Of Rs. 6,450 Due In 4 Years At 5% Per Annum Simple Interest?

Answer :

Let the annual installment be rs. X

consequently (x + x*3*5/a hundred)+(x + x*2*5/one hundred)

+(x + x*1*five/one hundred)+x =6450

=>115x/100+110x/100+105x/100+x=6450

=>115x+110x+105x+100x=6450*one hundred

=>430x=6450*one hundred

x=6450*one hundred/430=rs.1500

SAP BASIS Tutorial
Question 5. The Average Of The First one hundred Positive Integers Is?

Answer :

n(n+1)/2

1+2+3+....+n

therefore average of these numbers=n+1/2

therefore required common

100+1/2=50.5

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Question 6. In A Family, The Average Age Of A Father And A Mother Is 35 Years. The Average Age Of The Father, Mother And Their Only Son Is 27 Years. What Is The Age Of The Son?

Answer :

Father+Mother=2*35=70 years

Father+Mother+Son=27*3=81 years

consequently Son's age=eighty one-70=eleven years

Question 7. The Length And Breadth Of A Rectangle Are Increased By 20% And forty% Respectively. What Is The Percentage Increase In Its Area?

Answer :

Apply the share formulation.

The percent increase in the place might be P + Q + PQ / a hundred.

So we get the answer as 20 +forty + 20 × 40/one hundred = 68%. 

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Question eight. The Diameter Of A Circle Is 21 Metres. It Will Take How Many Revolutions To Cover A Distance Of 6.6 Km?

Answer :

No. Of revolutions = Distance/circumference.

Distance = 6.6 × one thousand = 6600 metres.

Circumference = 2 × 22/7 × 21/2 = 66 metres.

No. Of revolutions = 6600/66 = 100 revolutions.

Question nine. If Shalu Buys 6 More Apples, His Carton Will Weigh 14.Five Kilograms.If The Weight Of One Apple Is 250 Grams.How Many Apples Did He Initially Had In His Carton?

Answer :

Weight of one apple = 250 g

Weight of 6 apples = 250 * 6= 1.5 kg

Initial weight = 14.Five – 1.Five= thirteen kg

Number of apples in his carton first of all :

= 13000/250

=52 apples

Aptitude Interview Questions
Question 10. A Tailor Has 37.Five Metres Of Cloth And He Has To Make 8 Piecesout Of A Metre Of Cloth. How Many Pieces Can He Make Out Of This Cloth?

Answer :

The tailor has to make eight piece from 1 metre.

So for 1 piece ,the dimension will be 1/eight=0.One hundred twenty five m

from 37.Five m tailor can get 37.5/0.A hundred twenty five = three hundred portions

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Question 11. How Many Digits Will Be There To The Right Of The Decimal Point In The Product Of ninety five.75 And .02554 ?

Answer :

Sum of decimal places = 7.

Since the closing digit to the extreme right could be zero (due to the fact that 5 x four = 20),

so there may be 6 huge digits to the right of the decimal point.

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Question 12. If A Person Walks At 14 Km/hr Instead Of 10 Km/hr, He Would Have Walked 20 Km More. The Actual Distance Travelled By Him Is?

Answer :

Let the actual distance travelled be x km.

Then, x/10=x + 20/14

14x = 10x + 2 hundred

4x = 2 hundred

x= 50 km.

SAP BASIS Interview Questions
Question thirteen. In A Flight Of 600 Km, An Aircraft Was Slowed Down Due To Bad Weather. Its Average Speed For The Trip Was Reduced By two hundred Km/hr And The Time Of Flight Increased By 30 Minutes. The Duration Of The Flight Is?

Answer :

Let the duration of the flight be x hours.

Then,600/x-600/x + (1/2)= 200

600/x-1200/2x + 1= two hundred

x(2x + 1) = three

2x2 + x - three = zero

(2x + 3)(x - 1) = zero

x= 1 hr. 

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Question 14. In Covering A Distance Of 30 Km, Abhay Takes 2 Hours More Than Sameer. If Abhay Doubles His Speed, Then He Would Take 1 Hour Less Than Sameer. Abhay's Speed Is?

Answer :

Let Abhay's pace be x km/hr.

Then,30/x-30/2x= 3

 6x = 30

 x = five km/hr.

Question 15. Robert Is Travelling On His Cycle And Has Calculated To Reach Point A At 2 P.M. If He Travels At 10 Kmph, He Will Reach There At 12 Noon If He Travels At 15 Kmph. At What Speed Must He Travel To Reach A At 1 P.M.?

Answer :

Let the gap travelled by x km.

Then,x/10-x/15= 2

 3x - 2x = 60

 x = 60 km.

Time taken to journey 60 km at 10 km/hr =[60/10]hrs= 6 hrs.

So, Robert started out 6 hours before 2 P.M. I.E., at eight A.M.

Required pace =[60/5]kmph.= 12 kmph.

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Question sixteen. It Takes Eight Hours For A six hundred Km Journey, If a hundred and twenty Km Is Done By Train And The Rest By Car. It Takes 20 Minutes More, If 200 Km Is Done By Train And The Rest By Car. The Ratio Of The Speed Of The Train To That Of The Cars Is?

Answer :

Let the rate of the educate be x km/hr and that of the auto be y km/hr. 

Then,one hundred twenty/x+480/y= 8  -> 1/x+4/y =1/15...(1)

And,2 hundred/x+400/y=25/three-> 1/x+2/y =1/24....(2)

solving(1)and(2)we get: x = 60 and y = eighty.

Ratio of speeds=60:eighty=three:4.

Question 17. A Farmer Travelled A Distance Of 61 Km In nine Hours. He Travelled Partly On Foot @ four Km/hr And Partly On Bicycle @ 9 Km/hr. The Distance Travelled On Foot Is?

Answer :

Let the distance travelled strolling be x km.

Then, distance travelled on bicycle=(61 -x)km.

So,x/4+(61 -x)/nine= nine

9x + four(61 -x) = nine x 36

5x = eighty

x = sixteen km.

TCS Technical Interview Questions
Question 18. A Man Covered A Certain Distance At Some Speed. Had He Moved three Kmph Faster, He Would Have Taken forty Minutes Less. If He Had Moved 2 Kmph Slower, He Would Have Taken forty Minutes More. The Distance (in Km) Is?

Answer :

Let distance = x km and ordinary rate = y kmph.

Then,x/y-x/y+3=forty/60 -> 2y(y + 3) = 9x ....(i)     

And,x/y -2-x/y=40/60 -> y(y - 2) = 3x ....(ii)

On dividing (i) with the aid of (ii), we get: x = forty.

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Question 19. A Bike Runs At The Speed Of 50 Km/h When Not Serviced And Runs At 60 Km/h When Serviced. After Servicing The Bike Covers A Certain Distance In 6 H. How Much Time Will The Car Take To Cover The Same Distance When Not Serviced?

Answer :

From the given records, after servicing pace of the motorcycle = 60 km/h

Distance protected in 6h. = (60 * 6) km = 360km

When it’s now not service,the time taken to cover 360 km = (360 / 50) = 7.2h

Question 20. Present Ages Of Sameer And Anand Are In The Ratio Of five : four Respectively. Three Years Hence, The Ratio Of Their Ages Will Become eleven : 9 Respectively. What Is Anand's Present Age In Years?

Answer :

Let the existing a long time of Sameer and Anand be 5x years and 4x years respectively.

Then, 5x + three/4x + three=11/nine

         9(5x + three) = eleven(4x + three)

         45x + 27 = 44x + 33

         45x - 44x = 33 - 27

         x = 6.

        Anand's present age = 4x = 24 years.

Wipro Aptitude Interview Questions
Question 21. A Man Is 24 Years Older Than His Son. In Two Years, His Age Will Be Twice The Age Of His Son. The Present Age Of His Son Is?

Answer :

Let the son's gift age be x years. Then, man's gift age = (x + 24) years.

 (x + 24) + 2 = 2(x + 2)

 x + 26 = 2x + 4

 x = 22.

Question 22. Six Years Ago, The Ratio Of The Ages Of Kunal And Sagar Was 6 : five. Four Years Hence, The Ratio Of Their Ages Will Be 11 : 10. What Is Sagar's Age At Present?

Answer :

Let the a long time of Kunal and Sagar 6 years in the past be 6x and 5x years respectively.

Then, (6x + 6) + 4/(5x + 6) + four  =11/10

          10(6x + 10) = 11(5x + 10)

          5x = 10     

          x = 2.

Sagar's present age = (5x + 6) = 16 years.

Question 23. The Sum Of The Present Ages Of A Father And His Son Is 60 Years. Six Years Ago, Father's Age Was Five Times The Age Of The Son. After 6 Years, Son's Age Will Be?

Answer :

Let the existing a long time of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = five(x - 6)

 54 - x = 5x - 30

 6x = eighty four

 x = 14.

Son's age after 6 years = (x+ 6) = two decades..

ABB Group Aptitude Interview Questions
Question 24. Two, Trains, One From Howrah To Patna And The Other From Patna To Howrah, Start Simultaneously. After They Meet, The Trains Reach Their Destinations After nine Hours And 16 Hours Respectively. The Ratio Of Their Speeds Is?

Answer :

Let us name the trains as A and B. Then,

(A's pace) : (B's pace) = b : a = 16 : 9 = 4 : 3.

SAP FICO Interview Questions
Question 25. Tickets Numbered 1 To 20 Are Mixed Up And Then A Ticket Is Drawn At Random. What Is The Probability That The Ticket Drawn Has A Number Which Is A Multiple Of three Or 5?

Answer :

Here, S = 1, 2, three, 4, ...., 19, 20.

Let E = event of having a a couple of of three or 5 = 3, 6 , 9, 12, 15, 18, five, 10, 20.

P(E) =   n(E)/ n(S)=nine/20.

Question 26. What Is The Probability Of Getting A Sum 9 From Two Throws Of A Dice?

Answer :

In  throws of a dice, n(S) = (6 x 6) = 36.

Let E = occasion of having a sum =(three, 6), (4, 5), (five, four), (6, three).

P(E) =   n(E)/ n(S)=four/36 =1/nine.

TCS Aptitude Interview Questions
Question 27. A Bag Contains 6 Black And 8 White Balls. One Ball Is Drawn At Random. What Is The Probability That The Ball Drawn Is White?

Answer :

Let wide variety of balls = (6 + eight) = 14.

Number of white balls = eight.

P (drawing a white ball) =eight/14=4/7.

Aptitude Interview Questions
Question 28. What Is The Average Candidates Who Appeared From State Q During The Given Years?

Answer :

Required average=8100 + 9500 + 8700 + 9700 + 8950/five

=44950/five

= 8990.

Question 29. What Are The Average Marks Obtained By All The Seven Students In Physics?

Answer :

Average marks obtained in Physics by all of the seven students

=1/7x [ (90% of 120) + (80% of 120) + (70% of 120) + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120) ]

=1/7x [ (90 + 80 + 70 + 80 + 85 + 65 + 50)% of 120 ]

=1/7x [ 520% of 120 ]

=624/7

= 89.14.

Question 30. What Was The Aggregate Of Marks Obtained By Sajal In All The Six Subjects?

Answer :

Aggregate marks acquired by means of Sajal

= [ (90% of 150) + (60% of 130) + (70% of 120) + (70% of 100) + (90% of 60) + (70% of 40) ]

= [ 135 + 78 + 84 + 70 + 54 + 28 ]

= 449.

Question 31. There Are Two Examinations Rooms A And B. If 10 Students Are Sent From A To B, Then The Number Of Students In Each Room Is The Same. If 20 Candidates Are Sent From B To A, Then The Number Of Students In A Is Double The Number Of Students In B. The Number Of Students In Room A Is?

Answer :

Let the variety of college students in rooms A and B be x and y respectively.

Then, x - 10 = y + 10      x - y = 20 .... (i)

and x + 20 = 2(y - 20)      x - 2y = -60 .... (ii)

Solving (i) and (ii) we get: x = 100 , y = eighty.

The required solution A = a hundred.

Question 32. A Man Has Some Hens And Cows. If The Number Of Heads Be 48 And The Number Of Feet Equals 140, Then The Number Of Hens Will Be?

Answer :

Let the range of hens be x and the quantity of cows be y.

Then, x + y = forty eight .... (i)

and 2x + 4y = 140      x + 2y = 70 .... (ii)

Solving (i) and (ii) we get: x = 26, y = 22.

The required solution = 26.