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Top 100+ Igate Aptitude Interview Questions And Answers

Question 1. If 35% Of 30 = 25% Of X + 1, Find The Value Of X ?

Answer :

35% of 30=25% of X+1

35*30/100= 25*X/a hundred+1

one zero five/10=X/four +1

X=38

Question 2. Shiva Purchased 40 Shirts For Rs.3000. He Spends 10% On Transportation. What Should Be The Selling Price Per Shirt To Gain A Profit Of 20% ?

Answer :

Total cost rate of 40 shirts which includes transportation = 3000+ (3000*10)/one hundred = 3300

Given profit = 20%

Hence, Selling rate = (a hundred+20)*3300/one hundred

S.P of 40 shirts = 3960

So S.P. Of one shirt = 3960/forty= Rs.99

Aptitude Interview Questions
Question 3. If A Man Travels With 5/6th Of His Usual Speed, He Is Late By 15 Mins. What Is The Usual Time Taken To Travel ?

Answer :

Suppose man's regular pace = s, and normal time = t

So distance = speed *time ==> d= s*t

If he travels with five/sixth of his regular pace that is = s*five/6

And time= (t+15) and distance, d = (s*5/6)*(t+15) as distance could be same

s*t = (s*5/6)*(t+15)

t= (5t+seventy five)/6

t= 75 min.

Question four. If The Current Age Of Ram's Father Is Thrice Of Age Of Ram. Then After 10 Years, The Age Of Father Will Be 2 Times The Age Of Ram. The Current Age Of Ram Is ?

Answer :

Let take modern-day age of Ram= x, modern age of dad = 3x

After 10 years, Ram age = x+10, Father's age= 3x+10

As in step with circumstance:

3x+10= 2*(x+10)

3x+10 = 2x+20

X= 10 years

Question 5. The Average Age Of Five Girls In A Hostel Is eleven. The Oldest Girl Among Them Is 15 Years Old. What Is The Average Age Of The Other Girls ?

Answer :

As in line with question, the common age of 5 girls is 15, Lets X be the full age of the ladies

X/5= eleven

X= fifty five

Oldest girl age+ last four ladies age= 55

Remaining 4 girls age= 55-15==> 40

Average age of four girls = 40/four= 10 years.

IGate Technical Interview Questions
Question 6. The Cost Price Of A Bed Is Rs.2400 Which Is 20% Below The Market Price If It Is Sold At A Discount Of 16% On The Market Price Then Find Its Market Price, Selling Price And Profit ?

Answer :

Cost fee of mattress= Rs.2400

Let's take market fee of mattress = X

As the question

C.P= (X-20X)/a hundred

C.P= eighty*X/100 -> 2400=eight*X/10

X = Rs.3000.

-> S.P = 3000 ? (sixteen*3000)/one hundred

Selling Price = 2520

-> Profit = 2520- 2400 ==> 120Rs.

%income = a hundred and twenty*a hundred/2400= 5%

Question 7. In How Many Ways Letters Of World "main" Can Be Arranged, So That Vowels Always Come Together ?

Answer :

LEADING phrase may be written as "L" "E" "A" "D" "I" "N" "G"

Taking vowels together = E A I, so vowels can be arranged as= !3 ways and shall we Vowels be a unit X

So X L D N G, It can be arranged in = !Five Ways

So entire phrase can be written in= !Three *! Five = 720 ways

ABB Group Aptitude Interview Questions
Question 8. If The First Day Of Year Is Monday. Then What Is The Last Day Of The Year, If It's Not A Leap Year.

Answer :

Since the yr isn't always soar 12 months hence peculiar day might be = 1 day

So 1's day of next year can be = (Monday+ atypical day) => Tuesday

So last day of that 12 months = Monday

Question nine. A And B Can Complete A Work In 30 Days, Working Together. Both Worked For 20 Days And Then B Left The Work. The Remaining Work Was Completed By A Alone In 20 More Days. So In How Many Days B Alone Can Complete The Entire Work.

Answer :

(A+B)'s 1-day paintings, while working together= 1/30

(A+B)'s 20 days' paintings= 20/30==> 2/three

Remaining work = (1-2/3) ===> 1/three

Remaining paintings was carried out with the aid of A in 20 extra days = 1/three

So A can complete the complete paintings by myself in = 20* 3 ===>60 days

Hence A's 1-day paintings, working alone = 1/60

B?S 1 day work, working on my own = 1/30-1/60======1/60

So B will take 60 days to for completing the whole phrase.

TCS Aptitude Interview Questions
Question 10. Find The Value Of (483*483*483+ 517*517*517) / (517*517 - 517*483 + 483*483) ?

Answer :

(483*483*483+ 517*517*517) / (517*517 - 517*483 + 483*483) a3+b3

= (a+b)(a2-ab+b2) Hence [(a+b)(a2-ab+b2)] / (a2-ab+b2)

= a+b In the given equation a=483 and b= 517

==> 483+517=1000.

Question eleven. A' And 'b' Complete A Work Together In eight Days.If 'a' Alone Can Do It In 12 Days.Then How Many Day 'b' Will Take To Complete The Work?

Answer :

A & B someday work = 1/8

A by myself sooner or later work = 1/12

B by myself someday work = (1/eight - 1/12) = ( 3/24 - 2/24)

=> B sooner or later work = 1/24

so B can entire the paintings in 24 days.

Infosys Aptitude Interview Questions
Question 12. The Respective Ratio Of Radii Of Two Right Circular Cylinders (a And B) Is four : 5. The Respective Ratio Of Volume Of Cylinders A And B Is 12:25. What Is The Respective Ratio Of The Heights Of Cylinders A And B?

Answer :

Volume = πr2h

π*four*four*hA / π*5*5*hB = 12/25

Solving, hA/ hB = three:4

Aptitude Interview Questions
Question 13. The Tax On A Commodity Is Diminished By 10 % And Its Consumption Increased By 10 %. The Effect On The Revenue Derived From It Changes By K %. Find The Value Of K.

Answer :

Directly using the formula, when a value is increased through R% and then reduced through R%, then internet there is ( R∧2)/a hundred lower. Putting R = 10, we get 1% decrease.

Question 14. What Percent Of Selling Price Would Be 34 % Of Cost Price If Gross Profit Is 26 % Of The Selling Price ?

Answer :

X% of SP = 34% of CP

Also, P = 26% of SP

SP - CP = 0.26(SP)

CP = 0.Seventy four(SP)

Now, (34/100)×seventy four

X = 25.Sixteen

Question 15. P, Q And R Are Three Typists Who Working Simultaneously Can Type 216 Pages In four Hours. In One Hour, R Can Type As Many Pages More Than Q As Q Can Type More Than P. During A Period Of Five Hours, R Can Type As Many Pages As P Can During Seven Hours. How Many Pages Does Each Of Them Type Per Hour ?

Answer :

Let's the variety of pages typed in a single hour by P, Q and R be p, q and r respectively. Then,

P,Q and R typed web page in 1 hrs = 216/4

=> p + q + r = 216/4

=> p + q + r = 54 ...(i)

r - q = q - p => 2p = q + r ...(ii)

5r = 7p => p = five/7 r ...(iii)

By Solving above (i), (ii) and (iii) equations

=> p = 15, q = 18, q = 21

IBM Aptitude Interview Questions
Question 16. The Retail Price Of A Water Geyser Is Rs. 1,265. If The Manufacturer Gains 10 %, The Wholesale Dealer Gains 15 % And The Retailer Gains 25 %, Then The Cost Of The Product Is:

Answer :

C.P = 1265*a hundred*one hundred*100/one hundred ten/a hundred and fifteen/one hundred twenty five

C.P = 800

Question 17. Find The Number That Can Be Put In Place Of The Question Mark 5,6,?,87,412,2185.

Answer :

collection inside the shape of five*1+1^three=6,

6*2+2^3=20,

20*three+three^three=87,

87*four+4^3=412,

412*5+5^3=125.

Intuit Aptitude Interview Questions
Question 18. A, B And C Started A Business By Investing Rs. 40,500, Rs. Forty five,000 And Rs. 60,000 Respectively. After 6 Months C Withdrew Rs. 15,000 While A Invested Rs. 45,000 More. In Annual Profit Of Rs. Fifty six,100, The Share Of C Will Exceed That Of A By ?

Answer :

For 365 days the capital is

A = (40500 * 6 + 45000 * 6) = Rs. Five,13,000

B = (45000 * 12) = Rs. Five,forty,000

C = (60000 * 6 + 45000 * 6) = Rs. 6,30,000

Ratio A : B : C = 513 : 540 : 630

C's percentage will exceed that of A via

= [(630 - 513)/1683] * 56100 => (117/1683) * 56100

=> (117/3) * 100 = 39 * one hundred = Rs. 3900

IGate Technical Interview Questions
Question 19. 17.995/3.01 + 104.001/12.999 = ?

Answer :

18/three + 104/13 = 14

Question 20. Dhruva Gave 35% Of Her Monthly Salary To Her Mother. From The Remaining Salary, She Paid 18% Towards Rent And 42% She Kept Aside For Her Monthly Expenses. The Remaining Amount She Kept In Bank Account. The Sum Of The Amount She Kept In Bank And That She Gave To Her Mother Was Rs. Forty three,920. What Was Her Monthly Salary ?

Answer :

Let ‘x’ be the month-to-month salary, then

(sixty five/one hundred × forty/a hundred)x + 35/100x = 43920

Solving, X= 72000

Capgemini Aptitude Interview Questions
Question 21. If X: Y=3:5, Find The Ratio 3x+4y:8x+5y ?

Answer :

x:y=3:five

xy=35

5x=3y

x=3y5

3x+4y:8x+5y=three×3y5+4y:eight×3y5+5y=9y+20y5:24y+25y5=29y5:49y5=29y:49y=29:forty nine

Question 22. If X: Y=eight:nine, Find The Ratio (7x-4y):3x+2y ?

Answer :

x:y=8:nine

xy=89

9x=8y

x=8y9

7x−4y:3x+2y=7×8y9−4y:3×8y9+2y=56y−36y9:42y9=20:42=10:21

Question 23. Two Numbers Are In The Ratio 3:5. If eight Is Added To Each Number, The Ratio Becomes 2:3. Find The Numbers ?

Answer :

Let the required numbers be 3x and 5x

If eight is delivered to each other

3x+8:5x+eight=2:three

3x+85x+8=23

three(3x+8)=2(5x+8)

9x+24=10x+16

10x-9x=24-sixteen

x=8

Thus the numbers are 3x=three(eight)=24

5x=5(eight)=forty

Cognizant Aptitude Interview Questions
Question 24. What Should Be Added To Each Term Of The Ratio 7: 13 So That The Ratio Becomes 2: 3 ?

Answer :

Let the number to be delivered be x

Then

7+x13+x=23

(7+x)3=2(13+x)

3x-2x=26-21

x=five

Hence the specified variety is five

ABB Group Aptitude Interview Questions
Question 25. Three Numbers Are In The Ratio 2: three: five And The Sum Of These Numbers Is 800. Find The Numbers ?

Answer :

Given that

Three numbers are in ratio 2:three:5

Sum of those numbers=800

Sum of the phrases of the ratio=2+three+five=10

Firstnumber=210×800=160Secondnumber=310×800=240Thirdnumber=510×800=400

Question 26. The Ages Of Two Persons Are In The Ratio five: 7. Eighteen Years Ago Their Ages Were In The Ratio 8:13. Find Their Present Ages ?

Answer :

Let the required ages be 5x and 7x

18 years in the past their age ratios

5x−187x−18=813

65x−thirteen×18=eight×7x−eight×18

65x-234=56x-a hundred and forty four

65x-56x=234-one hundred forty four

9x=90

x=10

Thus the ages are 5x=5×10=50years

7x=7×10=70 years

EXL Service Aptitude Interview Questions
Question 27. Two Numbers Are In The Ratio 7:eleven. If 7 Is Added To Each Of The Numbers, The Ratio Becomes 2 . Three. Find The Numbers ?

Answer :

Let the specified numbers be 7x and 11x

If 7 is delivered to every of the numbers it turns into

7x+711x+7=23

21x+21=22x+14

X=21-14=7

Thus

The numbers are 7x=7×7=49

11x=11×7=seventy seven

TCS Aptitude Interview Questions
Question 28. Two Numbers Are In The Ratio 2: 7.11the Sum Of The Numbers Is 810. Find The Numbers ?

Answer :

Two numbers are in the ratio=2:7