Interview Questions.

Question 1. A Train Overtakes Two Persons Who Are Walking In The Same Direction In Which The Train Is Going, At The Rate Of 2 Kmph And four Kmph And Passes Them Completely In nine And 10 Seconds Respectively. The Length Of The Train Is ?

Answer :

2 kmph = ( 2 x5 /18)m/sec = five /9m/sec.

Four kmph = ( four x 518)m/sec = 10 /9m/sec.

Let the duration of the train be x metres and its speed by y m/sec.

Then, (x /y-five/9) = 9 and (x/y-10/nine )= 10.

9y-five=xand 10 (9y-10)=9x

9y-x=five and 90y-9x=100

on solving we get x=50

Length of the educate is 50 m

Question 2. A Man Rows To A Place forty eight Km Distant And Come Back In 14 Hours. He Finds That He Can Row 4 Km With The Stream In The Same Time As 3 Km Against The Stream. The Rate Of The Stream Is ?

Answer :

Suppose he pass four km downstream in x hours. Then,

Speed downstream =(4/x)km/hr

Speed up flow =(3/x)km/hr

forty eight/four/x+forty eight(3/x)=14 or x=half

So,speed downstream = 8 km/hr,pace upstream =6km/hr

Rate of the move = 1/2(8-6)km/hr =1 km/hr.

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Question 3. A Pupil's Marks Were Wrongly Entered As 83 Instead Of sixty three. Due To That The Average Marks For The Class Got Increased By Half (1/2). The Number Of Pupils In The Class Is ?

Answer :

Let there be x students inside the elegance.

Total increase in marks =(x*1/2)=x/2

Therefore x/2=(83-sixty three) =x/2=20 =x=40

Question four. Three Candidates Contested An Election And Received 1136, 7636 And 11628 Votes Respectively. What Percentage Of The Total Votes Did The Winning Candidate Get ?

Answer :

Total wide variety of votes polled = (1136 + 7636 + 11628) = 20400.

Required percent = (11628 / 20400 x one hundred) % = fifty seven%.

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Question 5. What Percent Of a hundred and twenty Are ninety ?

Answer :

(?% /100) * 120 = ninety

? = seventy five%

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Question 6. If Y Exceeds X By 20%, Then X Is Less Than Y By?

Answer :

X=one hundred y=one hundred twenty

120------20

100-------? => sixteen 2/3%

Question 7. How Much 60% Of 50 Is Greater Than forty% Of 30?

Answer :

(60/100) * 50 – (40/a hundred) * 30

30 - 12 = 18

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Question eight. Two Numbers Are Respectively 20% And 25% More Than A Third Number. The Percentage That Is First Of The Second Is ?

Answer :

I        II     III

a hundred and twenty  a hundred twenty five a hundred

125----------120

a hundred-----------? => 96%

Question nine. A Sells His Goods 50% Cheaper Than B But 50% Dearer Than C. The Cheapest Is ?

Answer :

Let B = 100

A = 50

C * (one hundred fifty/one hundred) = 50

3C = a hundred

C = 33.3 then 'C' Cheapest

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Question 10. The Salary Of A Typist Was At First Raised By 10% And Then The Same Was Reduced By 5%. If He Presently Draws Rs.1045.What Was His Original Salary ?

Answer :

X * (a hundred and ten/a hundred) * (95/100) = 1045

X * (11/10) * (1/one hundred) = eleven

X = 1000

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Question eleven. The Tax On A Commodity Is Diminished By 20% And Its Consumption Increased By 15%. The Effect On Revenue Is ?

Answer :

a hundred * one hundred = 10000

 80 * 115 =   9200

 10000-----------800

100-----------? => 8% decrease

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Question 12. A Candidate Got 35% Of The Votes Polled And He Lost To His Rival By 2250 Votes. How Many Votes Were Cast ?

Answer :

35%-----------L

sixty five%-----------W

30%----------2250

one hundred%---------? => 7500

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Question 13. If The Price Of Gold Increases By 50%, Find By How Much The Quantity Of Ornaments Must Be Reduced, So That The Expenditure May Remain The Same As Before?

Answer :

one hundred

150

a hundred and fifty-------50

one hundred-------? => 331/3%

Question 14. Subtracting 10% From X Is The Same As Multiplying X By What Number ?

Answer :

X - (10/100) X = X * ?

? = ninety%

Question 15. If The Numerator Of A Fraction Is Increased By 20% And Its Denominator Is Diminished By 25% Value Of The Fraction Is 2/15. Find The Original Fraction ?

Answer :

X * (one hundred twenty/a hundred) --- = 2/15

Y * (75/100)

X/Y = 1/12

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Question 16. Solve The Equation For X : 6x - 27 + 3x = four + 9 – X

Answer :

9 x + x = thirteen + 27

10 x = forty => x = four

Question 17. Solve The Equation For X : 19(x + Y) + 17 = 19(-x + Y) – 21.

Answer :

19x + 19y + 17 = -19x + 19y - 21

38x = -38 => x = -1

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Question 18. The Cost Of 10 Kg Of Apples Is Equal To The Cost Of 24 Kg Of Rice. The Cost Of 6 Kg Of Flour Equals The Cost Of 2 Kg Of Rice. The Cost Of Each Kg Of Flour Is Rs.20.50. Find The Total Cost Of 4 Kg Of Apples, three Kg Of Rice And 5 Kg Of Flour?

Answer :

Let the expenses of every kg of apples and each kg of rice be Rs.A and Rs.R respectively.

10a = 24r and six * 20.50 = 2r

a = 12/five r and r = 61.Five 

a = 147.6

Required general fee = 4 * 147.6 + 3 * 61.Five + 5 * 20.5

= 590.Four + 184.5 + 102.Five = Rs.877.40

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Question 19. The Tens Digit Of A Two-digit Number Is Two More Than Its Unit Digit. The Two-digit Number Is 7 Times The Sum Of The Digits. Find The Units Digits ?

Answer :

Let the 2-digit variety be 10a + b

a = b + 2 --- (1)

10a + b = 7(a + b) => a = 2b

Substituting a = 2b in equation (1), we get 

2b = b + 2 => b = 2

Hence the devices digit is: 2.

Question 20. The Sum Of The Digits Of A Two-digit Number Is 12. The Difference Of The Digits Is 6. Find The Number?

Answer :

Let the 2-digit quantity be 10a + b

a + b = 12 --- (1)

If a>b, a - b = 6

If b>a, b - a = 6

If a - b = 6, adding it to equation (1), we get

2a = 18 => a =nine

so b = 12 - a = 3

Number would be 93.

If b - a = 6, adding it to the equation (1), we get

2b = 18 => b = nine

a = 12 - b = three.

Number might be 39.

Therefore, Number could be 39 or ninety three.

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Question 21. In A Series Of Six Consecutive Even Numbers, The Sum Of The Second And Sixth Numbers Is 24. What Is The Fourth Number ?

Answer :

Let the numbers be x, x + 2, x + four, x + 6, x + 8 and x + 10.

Given (x + 2) + (x + 10) = 24

=> 2x + 12 = 24 => x = 6

The fourth range = x + 6 = 6 + 6 = 12.

Question 22. The Sum Of Five Consecutive Even Numbers Of Set X Is 440. Find The Sum Of A Different Set Of Five Consecutive Integers Whose Second Least Number Is 121 Less Than Double The Least Number Of Set X ?

Answer :

Let the five consecutive even numbers be 2(x - 2), 2(x - 1), 2x, 2(x + 1) and 2(x + 2)

Their sum = 10x = 440

x = 44 => 2(x - 2) = 84

Second least quantity of the other set = 2(84) - 121 = forty seven

This set has its least wide variety as 46.

Sum of the numbers of this set = 46 + forty seven + forty eight + 49 + 50

= forty eight - 2 + 48 - 1 + 48 + forty eight + 1 + forty eight + 2 => five(forty eight) = 240

Question 23. The Number Obtained By Interchanging The Two Digits Of A Two-digit Number Is Less Than The Original Number By 45. If The Sum Of The Two Digits Of The Number So Obtained Is 13, Then What Is The Original Number ?

Answer :

Let the number be in the shape of 10a + b

Number fashioned via interchanging a and b = 10b + a.

A + b = thirteen --- (1)

10b + a = 10a + b - forty five

forty five = 9a - 9b => a - b = 5 --- (2)

Adding (1) and (2), we get

2a = 18 => a = nine and b = four

The wide variety is: ninety four.

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Question 24. In A Three Digit Number, The Hundred Digit Is 2 More Than The Tens Digit And The Units Digit Is 2 Less Than The Tens Digit. If The Sum Of The Digits Is 18, Find The Number ?

Answer :

Let the three digit numbers be 100a + 10b + c

a = b + 2

c = b - 2

a + b + c = 3b = 18 => b = 6

So a = 8 and b = 4

Hence the three digit wide variety is: 864

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Question 25. When 2 Is Added To Half Of One-1/3 Of One-fifth Of A Number, The Result Is One-fifteenth Of The Number. Find The Number ?

Answer :

Let the range be

2 + half of[1/3(a/5)] = a/15

=> 2 = a/30 => a = 60

Question 26. Mudit's Age 18 Years Hence Will Be Thrice His Age Four Years Ago. Find Mudit's Present Age ?

Answer :

Let Mudit's gift age be 'm' years.

M + 18 = three(m - four)

=> 2m = 30 => m = 15 years.

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Question 27. Ten Years Ago, The Age Of Anand Was One-1/3 The Age Of Bala At That Time. The Present Age Of Bala Is 12 Years More Than The Present Age Of Anand. Find The Present Age Of Anand ?

Answer :

Let the present ages of Anand and Bala be 'a' and 'b' respectively.

A - 10 = 1/3 (b - 10) --- (1)

b = a + 12

Substituting b = a + 12 in first equation,

a - 10 = 1/three (a + 2) => 3a - 30 = a + 2

=> 2a = 32 => a = 16.

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Question 28. The Present Average Age Of A Couple And Their Daughter Is 35 Years. Fifteen Years From Now, The Age Of The Mother Will Be Equal To The Sum Of Present Ages Of The Father And The Daughter. Find The Present Age Of Mother ?

Answer :

(f + m + d)/three = 35

=> f + m + d = one zero five --- (1)

m + 15 = f + d

Substituting f + d as m + 15 in (1), we get

2m + 15 = 105

2m = 90 => m = forty five years.

Question 29. The Cost Of 16 Pens And 8 Pencils Is Rs.352 And The Cost Of four Pens And four Pencils Is Rs.Ninety six. Find The Cost Of Each Pen ?

Answer :

Let the price of every pen and pencil be 'p' and 'q' respectively.

16p + 8q = 352 --- (1)

4p + 4q = 96

8p + 8q = 192 --- (2)

(1) - (2) => 8p = one hundred sixty

=> p = 20

Question 30. A Bag Contains A Total Of 93 Coins In The Form Of One Rupee And 50 Paise Coins. If The Total Value Of Coins In The Bag Is Rs.Fifty six, Find The Number Of 50 Paise Coins In The Bag ?

Answer :

Let the quantity of one rupee coins in the bag be x.

Number of 50 paise coins within the bag is 93 - x.

Total cost of cash

[100x + 50(93 - x)]paise = 5600 paise

=> x = 74