## Tech Mahindra Aptitude Placement Papers - Tech Mahindra Aptitude Interview Questions and Answers

Q1. A Man Owns 2/3 Of The Market Research Beauro Business And Sells 3/four Of His Shares For Rs. 7500

three/4 of his share = 75000

so his percentage = one hundred thousand.

2/three of enterprise price = a hundred thousand

so overall cost = 150000

Q2. In A Mixture Of 35 Litres The Ratio Of Milk And Water Is 4 :

Mixture = 35L, Milk = four/5 × 35 =28L

Water = 1/five × 35 =7L

New 28/7+7 = M/W

⇒ 28/14 = M/W =2/1

Q3. X And Y Started A Business Together. If X Invested Rs. Sixteen,000 For 8 Months And Y Invested Some Amount In The Business For four Months. If Y Claims 2/7 Of The Total Profit Earned. How Much Money Was Inves

Lets expect the whole income = Rs. T

so Y component = 2*T/7 and

X component = T - 2*T/7 = 5*T/7

X, Y ratio

=> X : Y = five*T/7 : 2*T/7 = five : 2

Y invested Rs.P

so (16000 * eight) / (P * 4) = five/2

=> P = (16000 * 8 * 2) /(five * four)

=> P = Rs. 12800

Q4. A Person Spends forty% Of His Salary On Food, 25% On House Rent, 15% On Entertainment And 5% On Conveyance. If His Savings At The End Of The Month Is Rs. 1200, Then His Salary Per Month In Rupees Is:

Total expenditure = forty + 25 + 15 + five = eighty five%

Saving = (one hundred - eighty five) = 15%

15/one hundred × Salary = 1200, Salary = 8000 Rs.

Q5. Find The Mean Of The First Five Prime Numbers.

The first five prime numbers are 2, three, five, 7 and 11.

Mean = Sum of the primary five high numbers/quantity of prime numbers

= (2 + 3 + 5 + 7 + eleven)/5

= 28/5

= 5.6

Hence, their mean is 5.6

Q6. If The Mean Of nine, 8, 10, X, 12 Is 15, Find The Value Of X.

Mean of the given numbers = (9 + 8 + 10 + x + 12)/five = (39 + x)/five

According to the hassle, imply = 15 (given).

Therefore, (39 + x)/5 = 15

⇒ 39 + x = 15 × five

⇒ 39 + x = seventy five

⇒ 39 - 39 + x = 75 - 39

⇒ x = 36

Hence, x = 36.

Q7. A Train Running At Speed Of 126 Kmph. What Will Be The Length Of Train If It Cross A Tree In 5 Sec.

Formula Used: Distance = (Speed * Time)

convert the teach speed (Kmph) in to mps multiply through 5/18

pace (mps) = 126 * 5/18 = 35 mps

duration = ( 35 * 5 ) meter

= one hundred seventy five meter

Q8. 320m Long Train Is Running At 72 Kmph. How Much Time It Will Take To Cross A Platform Of 180m Long ?

Total Length = Platform Length + Train Length

So Total Length = 500m

convert the train pace (Kmph) in to mps multiply via five/18

velocity (mps) = 72 * five/18 = 20mps

Formula Used: Time = Distance/Speed

Time = (500 / 20 ) sec

= 25 sec

Q9. Ajay, Vijay And Sanjay Rent A Pasture. Ajay Puts 10 Oxen For 7 Months, Vijay Puts 12 Oxen For five Months And Sanjay Puts 15 Oxen For three Months For Grazing. If The Rent Of The Pasture Is Rs. A hundred seventy five, How Much

Ajay : Vijay : Sanjay = 10 * 7 : 12 * 5 : 15 * 3

= 70 : 60 : 45 = 14 : 12 : 9.

So Sanjay's hire = Rs. (175 * 9/35) = Rs. Forty five.

Q10. The Mean Of 40 Numbers Was Found To Be three

Calculated mean of forty numbers = 38.

Therefore, calculated sum of those numbers = (38 × forty) = 1520.

Correct sum of those numbers

= [1520 - (wrong item) + (correct item)]

= (1520 - 36 + 56)

= 1540.

Therefore, the proper mean = 1540/forty = 38.5.

Q11. If X Gets 25% More Than Y And Y Gets 20% More Than Z, The Share Of Z Out Of Rs. 740 Will Be:

Z percentage = Z,

Y = 1.2Z

X = 1.25×1.2Z,

X+Y+Z =740

(1.25× 1.2+1.2+1)Z=740

three.7Z=740, Z=200

Q12. The Mean Of The Heights Of 6 Boys Is 152 Cm. If The Individual Heights Of Five Of Them Are 151 Cm, 153 Cm, a hundred and fifty five Cm, 149 Cm And 154 Cm, Find The Height Of The Sixth Boy.

Mean top of 6 boys = 152 cm.

Sum of the heights of 6 boys = (152 × 6) = 912 cm

Sum of the heights of five boys = (151 + 153 + 155 + 149 + 154) cm = 762 cm.

Height of the sixth boy

= (sum of the heights of 6 boys) - (sum of the heights of 5 boys)

= (912 - 762) cm = one hundred fifty cm.

Hence, the peak of the 6th female is 150 cm.

Q13. What Will Be The Income Tax Payable By A Person Getting A Taxable Income Of Rs. 30,000 During The Year If The First Rs. 18000 Is Not Taxable And The Tax Rates Are 25% Of The Next Rs. 12000 ?

T.I.=30,000, N.T.I.=18000

Taxable 12000, Income Tax = 25% of Taxable Income

= 1/4 ×: 12000 = RS.3000

Q14. Anirudh, Harish And Sahil Invested A Total Of Rs.1,35,000 In The Ratio 5:6:four Anirudh Invested Has Capital For 8 Months. Harish Invested For 6 Months And Sahil Invested For four Months. If They Earn A Pro

Anirudh make investments for 8 months,haris invested for six and

sahil for four months in the ratio of five:6:4

so ratio = five*eight : 6*6 : four*4

=> forty:36:16

=> 10:nine:four

So sahil's income=(4/23)*75900 = 13200

Q15. Find The Mean Of The First Six Multiples Of 4.

The first six multiples of 4 are 4, eight, 12, sixteen, 20 and 24.

Mean = Sum of the primary six multiples of 4/range of multiples

= (4 + 8 + 12 + sixteen + 20 + 24)/6

= 84/6

= 14.

Hence, their mean is 14.

Q16. A Train Running At The Speed Of 60 Km/hr Crosses A Pole In 9 Seconds. What Is The Length Of The Train ?

Length of the teach = (Speed x Time) =50/three x nine m = 150 m.

Q17. An Article When Sold At A Gain Of five% Yields Rs. 15 More Than When Sold At A Loss Of 5%. The Cost Price Of The Article Is:

10/a hundred × x = 15 ⇒ x=one hundred fifty

As the loss and income each are earned on the value price.

Q18. The Difference Between Ages Of A Man And His Daughter Is 2

Let the daughter’s modern age be x.

The current age of dad = 28+x

According to the question, the averages of their ages is 28.

Hence, (x+28+x)/2 =28

X =14.

Therefore, the daughter’s gift age is 14 and the daddy’s gift age is 42

Q19. A Train Overtakes Two Persons Walking Along A Railway Track. The First One Walks At four.Five Km/hr. The Other One Walks At 5.4 Km/hr. The Train Needs 8.4 And 8.Five Seconds Respectively To Overtake Them. If B

Convert the Speed in m/sec

so four.5 km/hr = ( four.5 x five/18 ) m/sec = 5/four m/sec = 1.25 m/sec,

and five.4 km/hr = ( 5.Four x 5/18 ) m/sec = three/2 m/sec = 1.Five m/sec.

Here anticipate the velocity of the train as x m/sec.

So relative can be (x-1.25) and (x - 1.Five)

(x - 1.25) x eight.4 = (x - 1.5) x eight.Five

=> 8.4x - 10.Five = eight.5x - 12.Seventy five

=> 0.1x = 2.25

=> x = 22.Five m/s

As alternatives are given in km/hr so convert the velocity mps to kmph

So Speed of the train = ( 22.5 x 18/five ) km/hr = 81 km/hr.

Q20. 10 Men Can Finish A Piece Of Work In 10 Days Whereas It Takes 12 Women To Finish It In 10 Days. If 15 Men And 6 Women Undertake To Complete The Work, How Many Days Will They Take To Complete The Work?

10 men = 10 days, 1 guys 1 day = 1/one hundred paintings

12 girls = 12 days, 1 girls 1 day = 1/one hundred twenty

15 guys + 6 ladies, 15 × 1/one hundred + 6 × 1/a hundred and twenty

3/20 +1/20= 4/20 =1/5 work= 5 days

Q21. A, B, C Are Partners In A Business. During A Particular Year. A Received One Third Of The Profit. B Received One Fourth Of The Profit And C Received The Remaining Rs. 500

Lets count on Total profit x

x * (1-1/three-1/four) = 5000

=> x*(12-4-three)/12 = 5000

x = 5000*12/5 = Rs. 12000

so A's proportion = Rs. (1/three*12000) = Rs. 4000

Q22. A Train Overtakes Two Persons Who Are Walking In The Same Direction In Which The Train Is Going, At The Rate Of 2 Kmph And 4 Kmph And Passes Them Completely In 19 And 20 Seconds Respectively. The Leng

Convert the individuals Speed in m/sec

2 kmph = (2 x five/18) m/sec = 5/9 m/sec.

Four kmph = (four x five/18 m/sec = 10/nine m/sec.

Let the length of the teach be x meters and its velocity by way of y m/sec.

Relative pace in recognize to each individual (y - five/nine) and (y - 10/9)

Formula Used: Time = Distance / velocity

so x / (y - five/9) = 19 ---- (1)

and x / (y - 10/9) = 20 ---- (2)

9x = 19 (9y - five) ----- (1)

9x = 20 (9y - 10) ------(2)

find the fee of x and y

19 (9y - 5) = 20(9y - 10)

171 y - ninety five = 180 y -2 hundred => 9y = one zero five => y = 105/nine = 35/three

Now discover the fee fo x via above any equations

9x = 171 *35/three - ninety five = 57 *35 - 95

9x = 1900 => x = 211.1 meter

Q23. The Heights Of Five Runners Are one hundred sixty Cm, 137 Cm, 149 Cm, 153 Cm And 161 Cm Respectively. Find The Mean Height Per Runner. Solution:

Mean peak = Sum of the heights of the runners/wide variety of runners

= (160 + 137 + 149 + 153 + 161)/five cm

= 760/5 cm

= 152 cm.

Hence, the imply height is 152 cm.

Q24. Find The Arithmetic Mean Of The First 7 Natural Numbers.

The first 7 natural numbers are 1, 2, three, four, 5, 6 and seven.

Let x denote their mathematics imply.

Then imply = Sum of the primary 7 herbal numbers/quantity of herbal numbers

x = (1 + 2 + three + 4 + 5 + 6 + 7)/7

= 28/7

= 4

Hence, their imply is 4.

Q25. A Merchant Marks His Wares 40% More Than The Real Price And Allows 20% Discount. His Profit Is:

Let the CP = one hundred Rs.

Mark Price = 140

Discount = 20%

Selling charge 80/a hundred × 140 = 112

Hence profit = 12%