Tech Mahindra Aptitude Placement Papers - Tech Mahindra Aptitude Interview Questions and Answers
Q1. A Man Owns 2/3 Of The Market Research Beauro Business And Sells 3/four Of His Shares For Rs. 7500
three/4 of his share = 75000
so his percentage = one hundred thousand.
2/three of enterprise price = a hundred thousand
so overall cost = 150000
Q2. In A Mixture Of 35 Litres The Ratio Of Milk And Water Is 4 :
Mixture = 35L, Milk = four/5 × 35 =28L
Water = 1/five × 35 =7L
New 28/7+7 = M/W
⇒ 28/14 = M/W =2/1
Q3. X And Y Started A Business Together. If X Invested Rs. Sixteen,000 For 8 Months And Y Invested Some Amount In The Business For four Months. If Y Claims 2/7 Of The Total Profit Earned. How Much Money Was Inves
Lets expect the whole income = Rs. T
so Y component = 2*T/7 and
X component = T - 2*T/7 = 5*T/7
X, Y ratio
=> X : Y = five*T/7 : 2*T/7 = five : 2
Y invested Rs.P
so (16000 * eight) / (P * 4) = five/2
=> P = (16000 * 8 * 2) /(five * four)
=> P = Rs. 12800
Q4. A Person Spends forty% Of His Salary On Food, 25% On House Rent, 15% On Entertainment And 5% On Conveyance. If His Savings At The End Of The Month Is Rs. 1200, Then His Salary Per Month In Rupees Is:
Total expenditure = forty + 25 + 15 + five = eighty five%
Saving = (one hundred - eighty five) = 15%
15/one hundred × Salary = 1200, Salary = 8000 Rs.
Q5. Find The Mean Of The First Five Prime Numbers.
The first five prime numbers are 2, three, five, 7 and 11.
Mean = Sum of the primary five high numbers/quantity of prime numbers
= (2 + 3 + 5 + 7 + eleven)/5
Hence, their mean is 5.6
Q6. If The Mean Of nine, 8, 10, X, 12 Is 15, Find The Value Of X.
Mean of the given numbers = (9 + 8 + 10 + x + 12)/five = (39 + x)/five
According to the hassle, imply = 15 (given).
Therefore, (39 + x)/5 = 15
⇒ 39 + x = 15 × five
⇒ 39 + x = seventy five
⇒ 39 - 39 + x = 75 - 39
⇒ x = 36
Hence, x = 36.
Q7. A Train Running At Speed Of 126 Kmph. What Will Be The Length Of Train If It Cross A Tree In 5 Sec.
Formula Used: Distance = (Speed * Time)
convert the teach speed (Kmph) in to mps multiply through 5/18
pace (mps) = 126 * 5/18 = 35 mps
duration = ( 35 * 5 ) meter
= one hundred seventy five meter
Q8. 320m Long Train Is Running At 72 Kmph. How Much Time It Will Take To Cross A Platform Of 180m Long ?
Total Length = Platform Length + Train Length
So Total Length = 500m
convert the train pace (Kmph) in to mps multiply via five/18
velocity (mps) = 72 * five/18 = 20mps
Formula Used: Time = Distance/Speed
Time = (500 / 20 ) sec
= 25 sec
Q9. Ajay, Vijay And Sanjay Rent A Pasture. Ajay Puts 10 Oxen For 7 Months, Vijay Puts 12 Oxen For five Months And Sanjay Puts 15 Oxen For three Months For Grazing. If The Rent Of The Pasture Is Rs. A hundred seventy five, How Much
Ajay : Vijay : Sanjay = 10 * 7 : 12 * 5 : 15 * 3
= 70 : 60 : 45 = 14 : 12 : 9.
So Sanjay's hire = Rs. (175 * 9/35) = Rs. Forty five.
Q10. The Mean Of 40 Numbers Was Found To Be three
Calculated mean of forty numbers = 38.
Therefore, calculated sum of those numbers = (38 × forty) = 1520.
Correct sum of those numbers
= [1520 - (wrong item) + (correct item)]
= (1520 - 36 + 56)
Therefore, the proper mean = 1540/forty = 38.5.
Q11. If X Gets 25% More Than Y And Y Gets 20% More Than Z, The Share Of Z Out Of Rs. 740 Will Be:
Z percentage = Z,
Y = 1.2Z
X = 1.25×1.2Z,
Q12. The Mean Of The Heights Of 6 Boys Is 152 Cm. If The Individual Heights Of Five Of Them Are 151 Cm, 153 Cm, a hundred and fifty five Cm, 149 Cm And 154 Cm, Find The Height Of The Sixth Boy.
Mean top of 6 boys = 152 cm.
Sum of the heights of 6 boys = (152 × 6) = 912 cm
Sum of the heights of five boys = (151 + 153 + 155 + 149 + 154) cm = 762 cm.
Height of the sixth boy
= (sum of the heights of 6 boys) - (sum of the heights of 5 boys)
= (912 - 762) cm = one hundred fifty cm.
Hence, the peak of the 6th female is 150 cm.
Q13. What Will Be The Income Tax Payable By A Person Getting A Taxable Income Of Rs. 30,000 During The Year If The First Rs. 18000 Is Not Taxable And The Tax Rates Are 25% Of The Next Rs. 12000 ?
Taxable 12000, Income Tax = 25% of Taxable Income
= 1/4 ×: 12000 = RS.3000
Q14. Anirudh, Harish And Sahil Invested A Total Of Rs.1,35,000 In The Ratio 5:6:four Anirudh Invested Has Capital For 8 Months. Harish Invested For 6 Months And Sahil Invested For four Months. If They Earn A Pro
Anirudh make investments for 8 months,haris invested for six and
sahil for four months in the ratio of five:6:4
so ratio = five*eight : 6*6 : four*4
So sahil's income=(4/23)*75900 = 13200
Q15. Find The Mean Of The First Six Multiples Of 4.
The first six multiples of 4 are 4, eight, 12, sixteen, 20 and 24.
Mean = Sum of the primary six multiples of 4/range of multiples
= (4 + 8 + 12 + sixteen + 20 + 24)/6
Hence, their mean is 14.
Q16. A Train Running At The Speed Of 60 Km/hr Crosses A Pole In 9 Seconds. What Is The Length Of The Train ?
Length of the teach = (Speed x Time) =50/three x nine m = 150 m.
Q17. An Article When Sold At A Gain Of five% Yields Rs. 15 More Than When Sold At A Loss Of 5%. The Cost Price Of The Article Is:
10/a hundred × x = 15 ⇒ x=one hundred fifty
As the loss and income each are earned on the value price.
Q18. The Difference Between Ages Of A Man And His Daughter Is 2
Let the daughter’s modern age be x.
The current age of dad = 28+x
According to the question, the averages of their ages is 28.
Hence, (x+28+x)/2 =28
Therefore, the daughter’s gift age is 14 and the daddy’s gift age is 42
Q19. A Train Overtakes Two Persons Walking Along A Railway Track. The First One Walks At four.Five Km/hr. The Other One Walks At 5.4 Km/hr. The Train Needs 8.4 And 8.Five Seconds Respectively To Overtake Them. If B
Convert the Speed in m/sec
so four.5 km/hr = ( four.5 x five/18 ) m/sec = 5/four m/sec = 1.25 m/sec,
and five.4 km/hr = ( 5.Four x 5/18 ) m/sec = three/2 m/sec = 1.Five m/sec.
Here anticipate the velocity of the train as x m/sec.
So relative can be (x-1.25) and (x - 1.Five)
(x - 1.25) x eight.4 = (x - 1.5) x eight.Five
=> 8.4x - 10.Five = eight.5x - 12.Seventy five
=> 0.1x = 2.25
=> x = 22.Five m/s
As alternatives are given in km/hr so convert the velocity mps to kmph
So Speed of the train = ( 22.5 x 18/five ) km/hr = 81 km/hr.
Q20. 10 Men Can Finish A Piece Of Work In 10 Days Whereas It Takes 12 Women To Finish It In 10 Days. If 15 Men And 6 Women Undertake To Complete The Work, How Many Days Will They Take To Complete The Work?
10 men = 10 days, 1 guys 1 day = 1/one hundred paintings
12 girls = 12 days, 1 girls 1 day = 1/one hundred twenty
15 guys + 6 ladies, 15 × 1/one hundred + 6 × 1/a hundred and twenty
3/20 +1/20= 4/20 =1/5 work= 5 days
Q21. A, B, C Are Partners In A Business. During A Particular Year. A Received One Third Of The Profit. B Received One Fourth Of The Profit And C Received The Remaining Rs. 500
Lets count on Total profit x
x * (1-1/three-1/four) = 5000
=> x*(12-4-three)/12 = 5000
x = 5000*12/5 = Rs. 12000
so A's proportion = Rs. (1/three*12000) = Rs. 4000
Q22. A Train Overtakes Two Persons Who Are Walking In The Same Direction In Which The Train Is Going, At The Rate Of 2 Kmph And 4 Kmph And Passes Them Completely In 19 And 20 Seconds Respectively. The Leng
Convert the individuals Speed in m/sec
2 kmph = (2 x five/18) m/sec = 5/9 m/sec.
Four kmph = (four x five/18 m/sec = 10/nine m/sec.
Let the length of the teach be x meters and its velocity by way of y m/sec.
Relative pace in recognize to each individual (y - five/nine) and (y - 10/9)
Formula Used: Time = Distance / velocity
so x / (y - five/9) = 19 ---- (1)
and x / (y - 10/9) = 20 ---- (2)
9x = 19 (9y - five) ----- (1)
9x = 20 (9y - 10) ------(2)
find the fee of x and y
19 (9y - 5) = 20(9y - 10)
171 y - ninety five = 180 y -2 hundred => 9y = one zero five => y = 105/nine = 35/three
Now discover the fee fo x via above any equations
9x = 171 *35/three - ninety five = 57 *35 - 95
9x = 1900 => x = 211.1 meter
Q23. The Heights Of Five Runners Are one hundred sixty Cm, 137 Cm, 149 Cm, 153 Cm And 161 Cm Respectively. Find The Mean Height Per Runner. Solution:
Mean peak = Sum of the heights of the runners/wide variety of runners
= (160 + 137 + 149 + 153 + 161)/five cm
= 760/5 cm
= 152 cm.
Hence, the imply height is 152 cm.
Q24. Find The Arithmetic Mean Of The First 7 Natural Numbers.
The first 7 natural numbers are 1, 2, three, four, 5, 6 and seven.
Let x denote their mathematics imply.
Then imply = Sum of the primary 7 herbal numbers/quantity of herbal numbers
x = (1 + 2 + three + 4 + 5 + 6 + 7)/7
Hence, their imply is 4.
Q25. A Merchant Marks His Wares 40% More Than The Real Price And Allows 20% Discount. His Profit Is:
Let the CP = one hundred Rs.
Mark Price = 140
Discount = 20%
Selling charge 80/a hundred × 140 = 112
Hence profit = 12%