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Impetus Aptitude Placement Papers - Impetus Aptitude Interview Questions and Answers

Q1. Mahesh And Umesh Can Complete A Work In 10 Days And 15 Days Respectively. Umesh Starts The Work And After 5 Days Mahesh Also Joins Him In All The Work Would Be Completed In?

Umesh’s five day’s work = 5 x 1/15 = 1/3

Remaining paintings = (1 – 1/3) = 2/3 (1/10 +1/ 15) work is performed via both in 1 day

Therefore 2/three paintings is executed by using both in (6 x 2/3) = 4days.

The paintings changed into completed in 9 days.

Q2. In Covering Distance, The Speed Of A & B Are In The Ratio Of 3:four.A Takes 30min More Than B To Reach The Destination. The Time Taken By A To Reach The Destination Is?

Ratio of speed = 3:four

Ratio of time = 4:three

permit A takes 4x hrs, B takes 3x hrs

then 4x-3x = 30/60 hr

x = ½ hr

Time taken through A to attain the destination is 4x = four * ½ = 2 hr.

Q3. A Person Invests Money In Three Different Schemes For 6 Years, 10 Years And 12 Years At 10 %, 12 %, And 15 %. Simple Interest Respectively. At The Completion Of Each Scheme, He Gets The Same Interest.

Let the required ratio be x: 1: y.

Then S.I on Rs x for 6 years at 10% p.A = S.I on re.1 10 years at 12 %p.A

X × 10/a hundred × 6 = 1 × 12/a hundred × 10

=> X = 120/60 =2

S.I on Re.1 for 10 years at 12 % p.A = S. I on Rs. Y for 12 years at 15 % p.A

Therefore, (1 x 12/one hundred x 10) = (y x 15/a hundred x 12)

=> y = 120/180 = 2/three

Required ratio = 2 : 1 = 2/three = 6 : three : 2.

Q4. Twelve Men Can Complete A Work In 8 Days. Three Days After They Started The Work, 3 More Men Joined Them. In How Many Days Will All Of Them Together Complete Remaining Work?

1 guy’s sooner or later’s paintings = 1/96 12 men’s three day’s paintings = (3 x 1/eight) = three/eight

Remaining work = (1 – three/eight) = five/eight 15 guys’s 1 day’s work = 15/96

Now 15/ninety six paintings is done by means of them in 1day

Therefore 5/eight paintings could be carried out via them in (ninety six/15 x 5/eight) i.E., four days.

Q5. A Borrows Rs.800 At The Rate Of 12 % Per Annum. Simple Interest And B Borrows Rs.910 At The Rate Of 10 % Per Annum Simple Interest. In How Many Years Will Their Amounts At Debts Be Equal?

Let the required time be x years.

Then 800 + 800 x 12/100 × x = 910 + 910 x 10/100 × x

=> (96x -ninety one x) = 110

=> 5x =110

=> x =22.

Q6. A Discount Series Of 10%, 20% And 40% Is Equal To A Single Discount Of?

Original charge = Rs. 100

Price after first cut price = Rs. Ninety

Price after 2d discount = Rs. (eighty/one hundred × ninety) = Rs. 72

Price after 0.33 cut price = Rs. (60/a hundred × seventy two) = Rs. 43.20

Single cut price = (a hundred – 43.20) = fifty six.8%.

Q7. If Rs. 510 Be Divided Among A, B, C In Such A Way That A Gets 2/three Of What B Gets And B Gets 1/four Of What C Gets, Then Their Shares Are Respectively?

(A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/four

A:B = 2:3 and B:C = 1:4 = 3:12

A:B:C = 2:three:12

A;s percentage = 510 * 2/17 = Rs. 60

B's proportion = 510 * 3/17 = Rs. Ninety

C's proportion = 510 * 12/17 = Rs. 360.

Q8. If The Interest Is Payable Annually Than The Principal On Which The Compound Interest For 3 Years At 10% P.A Is Rs 33/- Is Given By?

Let the principal be Rs x.

Then X × (1 + 10/100)three – x = 331

=> (x × eleven/10 × eleven/10 × 11/10 - x) = 331

=> ((1331x-1000x)/1000) = 331

=> 331x = 331000

=> X = 1000

Hence the fundamental is Rs a thousand.

Q9. X Varies Inversely As Square Of Y. Given That Y = 2 For X =

Given x = okay/y2, wherein okay is a regular.

Now, y = 2 and x = 1 gives k = four.

X = 4/y2 => x = four/sixty two, while

y = 6 => x = 4/36 = 1/nine.

Q10. Megha Purchased one hundred twenty Calendars At A Rate Of Rs 3 Each And Sold 1/three Of Them At The Rate Of Rs. 4 Each. Half Of Them At The Rate Of Rs five Each And Rest At The Cost Price. Her Profit Per Cent Was?

CP of one hundred twenty calendars = 120 x three = Rs. 360

SP of forty at Rs. Four every = Rs. 40 x 4 = Rs.160

SP of 60 at Rs five every = Rs 60 x five = Rs. Three hundred

SP of closing 20 calendars = Rs 20 x 3 = 60

Total SP = Rs.( 160 + three hundred + 60) = 520

Profit % = 520 – 360 = 160

Profit % = a hundred and sixty/360 x a hundred = four hundred/nine.

Q11. A Certain Distance Covered At A Certain Speed. If Half Of This Distance Is Covered In Double The Time The Ratio Of The Two Speeds Is?

Let x kms be protected in y hours, then first pace = x / y km/hr

Again x/2 km is protected in 2y hrs

Therefore, new pace = (x/2 x 1/2y)km/hr

= (x/ 4y) km/hr

Ratio of speeds = x/y : x/4y = 1 : ¼

= four : 1.

Q12. A Tank Is Filled In 5 Hours By Three Pipes A, B And C. The Pipe C Is Twice As Fast As B And B Is Twice As Fast As A. How Much Time Will Pipe A Alone Take To Fill The Tank?

Suppose pipe A on my own takes x hours to fill the tank.

Then, pipes B and C will take x/2 and x/four hours respectively to fill the tank.

1/x + 2/x + four/x = 1/5

7/x = 1/five => x = 35 hrs.

Q13. Two Trains Approach Each Other At 30 Km/hr And 27km/hr From Two Places 342km Apart After How Many Hours Will They Meet?

Suppose the 2 trains meet after x hours, then

=> 30x + 27x = 342

=> 57x = 342

=> X = 6

So the two trains will meet after 6 hours.

Q14. The Average Monthly Income Of P And Q Is Rs. 505

Let P, Q and R represent their respective month-to-month earning.

Then, we've:

P + Q = (5050 * 2) = 10100 --- (i)

Q + R = (6250 * 2) = 12500 --- (ii)

P + R = (5200 * 2) = 10400 --- (iii)

Adding (i), (ii) and (iii), we get:

2(P + Q + R) = 33000 = P + Q + R = 16500 --- (iv)

Subtracting (ii) from (iv), we get, P = 4000.

P's month-to-month earnings = Rs. 4000.

Q15. A Can Do A Piece Of Work In 80 Days. He Works At It For 10 Days And Then B Alone Finishes The Work In 42 Days. The Two Together Could Complete The Work In?

A’s 10 days work = (10 x 1/eighty) = 1/eight

Remaining work = (1 -1/eight) = 7/8

Therefore 7/eight paintings is achieved by means of A in 42 days.

Whole work might be performed via A in (42 x 8/7)i.E.., forty eight days

Therefore, (A+ B)’s 1 day work = (1/eighty + 1/48) = eight/240 = 1/30.

A and B together can end it in 30days.

Q16. A, B And C Contract A Work For Rs. 55

Work to be done through C = (1 – 7/11) = four/11

Therefore, (A +B) = C = 7/11 : 4/11 = 7 : four

Therefore C’s share = Rs.(550 x four/eleven) = Rs. 2 hundred.

Q17. A Tank Is Filled By Three Pipes With Uniform Flow. The First Two Pipes Operating Simultaneously Fill The Tank In The Same During Which The Tank Is Filled By The Third Pipe Alone. The Second Pipe Fills

Suppose, first pipe on my own takes x hours to fill the tank. Then, 2nd and 1/3 pipes will take (x - five) and (x - 9) hours respectively to fill the tank.

1/x + 1/(x - 5) = 1/(x - nine)

(2x - 5)(x - 9) = x(x - 5)

x2 - 18x + 45 = 0

(x- 15)(x - three) = 0 => x = 15.

Q18. A Can Finish A Work In 18 Days B Can Do The Same Work In 15 Days. B Worked For 10 Days And Left The Job. In How Many Days, A Alone Can Finish The Remaining Work?

B's 10 day's work = 1/15 * 10 = 2/3

Remaining paintings = (1 - 2/3) = 1/three

Now, 1/18 paintings is achieved via A in 1 day.

1/3 work is carried out via A in (18 * 1/3) = 6 days.

Q19. Kruti Took A Loan At Simple Interest At 6 % In The First Year With An Increase Of zero.5 % In Each Subsequent Year. She Paid Rs. 3375 As Interest After 4 Years. How Much Loan Did She Take?

Let the loan taken be Rs. X , then

X × 6/one hundred × 1 + X × 6.5/one hundred × 1 + X × 7/a hundred × 1 + X × 7.5/100 × 1 = 3375

=> (6+ 6.5 +7 +7.5) × X/100 = 3375

=> X = (3375 × 100/27) = 12500.

Q20. Salaries Of Ravi And Sumit Are In The Ratio 2:

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.

Then, (2x + 4000)/(3x + 4000) = 40/57

6x = 68000 => 3x = 34000

Sumit's present revenue = (3x + 4000) = 34000 + 4000 = Rs. 38,000.

Q21. Two Pipes A And B Together Can Fill A Cistern In four Hours. Had They Been Opened Separately, Then B Would Have Taken 6 Hours More Than A To Fill Cistern. How Much Time Will Be Taken By A To Fill The Cis

Let the cistern be stuffed by means of pipe A alone in x hours.

Then, pipe B will fill it in (x + 6) hours.

1/x + 1/(x + 6) = 1/4

x2 - 2x - 24 = zero

(x - 6)(x + four) = 0 => x = 6.

Q22. Simple Interest On Rs.500 For four Years At 6.25 % Per Annum Is Equal To The Simple Interest On Rs. 400 At five % Per Annum For A Certain Period Of Time. The Period Of Time Is?

Let the required time period be x years.

Then 500 x four x 6.25/a hundred = 400 x five/100 × x

=> 20 x 6.25 = 20 × x

=> X = 6.25 = 625/one hundred = 25/four = 6 ¼ years.

Q23. A Sum Of Money Is To Be Distributed Among A, B, C, D In The Proportion Of five:2:four:

Let the stocks of A, B, C and D be 5x, 2x, 4x and 3x Rs. Respectively.

Then, 4x - 3x = one thousand => x = one thousand.

B's share = Rs. 2x = 2 * a thousand = Rs. 2000.

Q24. A Can Do A Price Of Work In 30days While B Can Do It In forty Days. In How Many Days Can A And B Working Together Do It?

(A +B)’s 1 day’s paintings = (1/30 + 1/40) = 7/a hundred and twenty

Time is taken by way of both to finish the paintings = a hundred and twenty/7 days

= 17 1/7 days.

Q25. A Cricketer Has A Certain Average For 10 Innings. In The Eleventh Inning, He Scored 108 Runs, There By Increasing His Average By 6 Runs. His New Average Is?

Let average for 10 innings be x. Then,

(10x + 108)/11 = x + 6

= 11x + 66 = 10x + 108

= x = 42.

New average = (x + 6) = 48 runs.

Q26. Ratio Of The Earnings Of A And B Is 4:

Let the unique income of A and B be Rs. 4x and Rs. 7x.

New earnings of A = one hundred fifty% 0f Rs. 4x = (a hundred and fifty/one hundred * 4x) = Rs. 6x

New income of B = seventy five% of Rs. 7x = (seventy five/one hundred * 7x) = Rs. 21x/4

6x:21x/four = 8:7

This does now not provide x. So, the given facts is insufficient.

Q27. Kabir Buys An Article With 25% Discount On Its Marked Price. He Makes A Profit Of 10 % By Selling It At Rs. 66

Original rate be Rs. X

C.P = (X – 25% of X) = 3X/4

S.P = (3X/four + 10% of 3X/four) = 33X/forty= 660

=> X = 800.

Q28. Two Pipes A And B Can Fill A Tank In 15 Min And 20 Min Respectively. Both The Pipes Are Opened Together But After four Min, Pipe A Is Turned Off. What Is The Total Time Required To Fill The Tank?

Part filled in four minutes = four(1/15 + 1/20) = 7/15

Remaining component = 1 - 7/15 = eight/15

Part crammed by means of B in 1 minute = 1/20

1/20 : 8/15 :: 1 ; x

x = 8/15 * 1 * 20 = 10 2/three min = 10 min 40 sec.

The tank could be full in (4 min. + 10 min. Forty sec) = 14 min 40 sec.

Q29. Subhash Purchased A Tape Recorder At nine/10th Of Its Selling Price And Sold It At 8% More Than Its S.P. His Gain Is?

S.P be Rs. X C.P paid by using Subhash = Rs. 9X/10

S.P obtained by using Subhash = Rs. (108% of Rs. X)

= Rs. 27X/25

Gain = Rs. (27X/25 – 9X/10)

= Rs. 9X/50 Gain = (9X/50 × 10/9X × a hundred)% = 20%.

Q30. A Large Tanker Can Be Filled By Two Pipes A And B In 60 And 40 Minutes Respectively. How Many Minutes Will It Take To Fill The Tanker From Empty State If B Is Used For Half The Time And A And B Fill I

Part crammed by way of (A + B) in 1 minute = (1/60 + 1/forty) = 1/24

Suppose the tank is filled in x minutes.

Then, x/2(1/24 + 1/40) = 1

x/2 * 1/15 = 1 => x = 30 min.

Q31. Bombay Express Left Delhi For Bombay At 14.30 Hours. Travelling At A Speed Of 60kmph And Rajadhani Express Left Delhi For Bombay On The Same Day At sixteen.30 Hours Travelling Speed Of 80kmph. How Far Away

Let the train meet at a distance of x km from Delhi.

Then x/60 –x/80 = 2

=> 4x -3x

=> x =480

Therefore, Required distance = 480km.

Q32. R And S Start Walking Towards Each Other At 10 Am At Speeds Of 3km/hr And 4km/hr Respectively. They Were Initially 17.5km Apart At What Time Do They Meet?

Suppose they meet after x hours , then 3x +4x = 17.Five

=> 7x = 17.5

=> X = 2.5hours

So they meet at 12: 30 p.M.

Q33. Rs.6000 Becomes Rs.7200 In 4 Years At A Certain Rate Of Interest. If The Rate Becomes 1.5 Times Of Itself. The Amount Of The Same Principle In 5 Years Will Be?

S.I on Rs. 600 for four Years = Rs (7200 - 600) = Rs 1200

Therefore Rate = (120000/24000) % p.A = five % p.A

New Rate = (five x 3/2) % = 15/2 % p.A

Required Amount = [6000 + (6000 x 5/100 x 15/2)]

= Rs(6000 + 2250) = Rs 8250.

Q34. A Cricketer Whose Bowling Average Is 12.Four Runs Per Wicket Takes 5 Wickets For 26 Runs And There By Decreases His Average By 0.

Let the quantity of wickets taken till the remaining suit be x. Then,

(12.4x + 26)/(x + five) = 12

= 12.4x + 26 = 12x + 60

= 0.4x = 34

= x = 340/4 = 85.

Q35. Seats For Mathematics, Physics And Biology In A School Are In The Ratio five:7:

Originally, permit the variety of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively. Number of increased sears are (one hundred forty% of 5x), (a hundred and fifty% of 7x) and (175% of 8x)

i.E., (140/a hundred * 5x), (150/a hundred * 7x) and (175/100 * 8x)

i.E., 7x, 21x/2 and 14x

Required ratio = 7x:21x/2:14x

= 14x : 21x : 28x = 2:3:four.

Q36. The Average Weight Of A, B And C Is 45 Kg. If The Average Weight Of A And B Be 40 Kg And That Of B And C Be forty three Kg, Then The Weight Of B Is?

Let A, B, C constitute their respective weights.

Then, we have:

A + B + C = (45 * three) = one hundred thirty five --- (i)

A + B = (forty * 2) = eighty --- (ii)

B + C = (forty three * 2) = 86 --- (iii)

Adding (ii) and (iii),

we get: A + 2B + C = 166 --- (iv)

Subtracting (i) from (iv), we get: B = 31

B's weight = 31 kg.

Q37. If 40% Of A Number Is Equal To Two-1/3 Of Another Number, What Is The Ratio Of First Number To The Second Number?

Let forty% of A = 2/3 B. Then,

40A/100 = 2B/three => 2A/5 = 2B/3

A/B = (2/three * five/2) = five/3

A:B = 5:three.

Q38. A Is 30% More Efficient Than B. How Much Time Will They, Working Together, Take To Complete A Job Which A Alone Could Have Done In 23 Days?

Ratio of instances taken by A and B = a hundred:130 = 10:13

Suppose B takes x days to do the paintings.

X = (23 * 13)/10 = 299/10

A's 1 day work = 1/23; B's 1 day work = 10/299

(A + B)'s 1 day work = (1/23 + 10/299) = 1/13

A and B collectively can complete the task in thirteen days.

Q39. The Ratio Of The Prices Of Three Different Types Of Cars Is 4:five:

Let the costs be 4X, 5X and seven X rupees

7X – 4X = 60000

=> X = 20000

Required price = 5X = Rs. A hundred thousand.

Q40. The Speeds Of A And B Are In The Ratio 3:

The time taken by B =(x-20/60)hrs = (x-1/three)hrs

Ratio of speeds = Inverse ratio of time taken

Therefore three: four =(x-1/three) : x

=>3x-1/3x=3/4

=> 12x -4 =9x

=> 3x =4

=> X=4/3 hrs.

X=1 1/three hours.

Required time = 1 1/three hrs.

Q41. The Captain Of A Cricket Team Of eleven Members Is 26 Years Old And The Wicket Keeper Is 3 Years Older. If The Ages Of These Two Are Excluded, The Average Age Of The Remaining Players Is One Year Less Tha

Let the average of the entire group be x years.

11x - (26 + 29) = nine(x - 1)

= 11x - 9x = forty six

= 2x = forty six => x = 23

So, average age of the crew is 23 years.

Q42. If The Rate Of Interest Be 4% Per Annum For First Year 5% Per Annum For The Second Year And 6% Per Annum From The Third Year Then The Compound Interest Of Rs 10000 For 3 Years Will Be?

Amount = Rs[10000 × (1 + 4/100) × (1 +5/100) × (1 × 6/100)]

= Rs(a thousand × 26/25 × 21/20 × fifty three/50)

= Rs (57876/5) = Rs 11575.20

C.I = Rs (11575.20 - 10000) = Rs 1575.20.

Q43. A Can Do (1/three) Of A Work In five Days And B Can Do (2/five) Of The Work In 10 Days. In How Many Days Both A And B Together Can Do The Work?

1/3 of work is performed through A in five days

Therefore, entire paintings can be finished by way of A in 15 days

2/five of labor is completed by way of B in 10 days

Whole work will be done with the aid of B in (10 x 5/2) i.E.., 25 days

Therefore (A + B)’s 1 day’s work = (1/15 + 1/25) = 8/seventy five

So both together can finish 75/eight days i.E.., 9 3/8 days.

Q44. The Ratio Between The Speed Of Two Trains Is 7: eight.If The Second Train Runs 400km In five Hours. The Speed Of The First Train Is?