Consagous Technologies Aptitude Placement Papers - Consagous Technologies Aptitude
Q1. If The Price Of Gold Increases By 50%, Find By How Much The Quantity Of Ornaments Must Be Reduced, So That The Expenditure May Remain The Same As Before?
one hundred fifty-------50
a hundred-------? => 331/3%
Q2. Subtracting 10% From X Is The Same As Multiplying X By What Number ?
X - (10/100) X = X * ?
? = ninety%
Q3. The Tens Digit Of A Two-digit Number Is Two More Than Its Unit Digit. The Two-digit Number Is 7 Times The Sum Of The Digits. Find The Units Digits ?
Let the two-digit wide variety be 10a + b
a = b + 2 --- (1)
10a + b = 7(a + b) => a = 2b
Substituting a = 2b in equation (1), we get
2b = b + 2 => b = 2
Hence the units digit is: 2.
Q4. The Number Obtained By Interchanging The Two Digits Of A Two-digit Number Is Less Than The Original Number By 4
Let the wide variety be inside the shape of 10a + b
Number formed by using interchanging a and b = 10b + a.
A + b = thirteen --- (1)
10b + a = 10a + b - forty five
forty five = 9a - 9b => a - b = 5 --- (2)
Adding (1) and (2), we get
2a = 18 => a = nine and b = 4
The number is: ninety four.
Q5. Mudit's Age 18 Years Hence Will Be Thrice His Age Four Years Ago. Find Mudit's Present Age ?
Let Mudit's gift age be 'm' years.
M + 18 = 3(m - four)
=> 2m = 30 => m = 15 years.
Q6. A Pupil's Marks Were Wrongly Entered As 83 Instead Of 6
Let there be x students in the magnificence.
Total growth in marks =(x*1/2)=x/2
Therefore x/2=(83-sixty three) =x/2=20 =x=40
Q7. What Percent Of a hundred and twenty Are 90 ?
(?% /100) * one hundred twenty = 90
? = seventy five%
Q8. If Y Exceeds X By 20%, Then X Is Less Than Y By?
X=100 y=one hundred twenty
a hundred-------? => 16 2/3%
Q9. A Train Overtakes Two Persons Who Are Walking In The Same Direction In Which The Train Is Going, At The Rate Of 2 Kmph And 4 Kmph And Passes Them Completely In 9 And 10 Seconds Respectively. The Lengt
2 kmph = ( 2 x5 /18)m/sec = 5 /9m/sec.
4 kmph = ( four x 518)m/sec = 10 /9m/sec.
Let the duration of the educate be x metres and its pace by using y m/sec.
Then, (x /y-5/9) = nine and (x/y-10/nine )= 10.
9y-five=xand 10 (9y-10)=9x
9y-x=5 and 90y-9x=a hundred
on fixing we get x=50
Length of the train is 50 m
Q10. How Much 60% Of 50 Is Greater Than forty% Of 30?
(60/100) * 50 – (forty/a hundred) * 30
30 - 12 = 18
Q11. The Cost Of 10 Kg Of Apples Is Equal To The Cost Of 24 Kg Of Rice. The Cost Of 6 Kg Of Flour Equals The Cost Of 2 Kg Of Rice. The Cost Of Each Kg Of Flour Is Rs.20.Five
Let the prices of every kg of apples and each kg of rice be Rs.A and Rs.R respectively.
10a = 24r and six * 20.50 = 2r
a = 12/5 r and r = 61.5
a = 147.6
Required general cost = four * 147.6 + three * sixty one.5 + 5 * 20.5
= 590.4 + 184.5 + 102.5 = Rs.877.40
Q12. If The Numerator Of A Fraction Is Increased By 20% And Its Denominator Is Diminished By 25% Value Of The Fraction Is 2/
X * (120/100) --- = 2/15
Y * (seventy five/a hundred)
X/Y = 1/12
Q13. Two Numbers Are Respectively 20% And 25% More Than A Third Number. The Percentage That Is First Of The Second Is ?
I II III
120 a hundred twenty five 100
a hundred twenty five----------a hundred and twenty
one hundred-----------? => ninety six%
Q14. In A Series Of Six Consecutive Even Numbers, The Sum Of The Second And Sixth Numbers Is 2
Let the numbers be x, x + 2, x + four, x + 6, x + 8 and x + 10.
Given (x + 2) + (x + 10) = 24
=> 2x + 12 = 24 => x = 6
The fourth range = x + 6 = 6 + 6 = 12.
Q15. In A Three Digit Number, The Hundred Digit Is 2 More Than The Tens Digit And The Units Digit Is 2 Less Than The Tens Digit. If The Sum Of The Digits Is 18, Find The Number ?
Let the three digit numbers be 100a + 10b + c
a = b + 2
c = b - 2
a + b + c = 3b = 18 => b = 6
So a = eight and b = 4
Hence the 3 digit range is: 864
Q16. Three Candidates Contested An Election And Received 1136, 7636 And 11628 Votes Respectively. What Percentage Of The Total Votes Did The Winning Candidate Get ?
Total quantity of votes polled = (1136 + 7636 + 11628) = 20400.
Required percent = (11628 / 20400 x 100) % = 57%.
Q17. The Sum Of Five Consecutive Even Numbers Of Set X Is 44
Let the five consecutive even numbers be 2(x - 2), 2(x - 1), 2x, 2(x + 1) and a pair of(x + 2)
Their sum = 10x = 440
x = forty four => 2(x - 2) = eighty four
Second least quantity of the opposite set = 2(84) - 121 = 47
This set has its least quantity as 46.
Sum of the numbers of this set = forty six + forty seven + 48 + 49 + 50
= 48 - 2 + 48 - 1 + 48 + 48 + 1 + forty eight + 2 => 5(forty eight) = 240
Q18. A Candidate Got 35% Of The Votes Polled And He Lost To His Rival By 2250 Votes. How Many Votes Were Cast ?
one hundred%---------? => 7500
Q19. When 2 Is Added To Half Of One-1/3 Of One-fifth Of A Number, The Result Is One-fifteenth Of The Number. Find The Number ?
Let the quantity be
2 + half[1/3(a/5)] = a/15
=> 2 = a/30 => a = 60
Q20. The Salary Of A Typist Was At First Raised By 10% And Then The Same Was Reduced By 5%. If He Presently Draws Rs.1045.What Was His Original Salary ?
X * (a hundred and ten/a hundred) * (ninety five/one hundred) = 1045
X * (11/10) * (1/a hundred) = eleven
X = a thousand
Q21. The Cost Of sixteen Pens And eight Pencils Is Rs.352 And The Cost Of four Pens And four Pencils Is Rs.Nine
Let the cost of each pen and pencil be 'p' and 'q' respectively.
16p + 8q = 352 --- (1)
4p + 4q = ninety six
8p + 8q = 192 --- (2)
(1) - (2) => 8p = one hundred sixty
=> p = 20
Q22. The Tax On A Commodity Is Diminished By 20% And Its Consumption Increased By 15%. The Effect On Revenue Is ?
A hundred * 100 = 10000
80 * 115 = 9200
100-----------? => 8% lower
Q23. A Bag Contains A Total Of 93 Coins In The Form Of One Rupee And 50 Paise Coins. If The Total Value Of Coins In The Bag Is Rs.Fifty six, Find The Number Of 50 Paise Coins In The Bag ?
Let the quantity of one rupee coins in the bag be x.
Number of fifty paise coins inside the bag is 93 - x.
Total value of cash
[100x + 50(93 - x)]paise = 5600 paise
=> x = 74
Q24. The Present Average Age Of A Couple And Their Daughter Is 35 Years. Fifteen Years From Now, The Age Of The Mother Will Be Equal To The Sum Of Present Ages Of The Father And The Daughter. Find The Pres
(f + m + d)/3 = 35
=> f + m + d = one zero five --- (1)
m + 15 = f + d
Substituting f + d as m + 15 in (1), we get
2m + 15 = a hundred and five
2m = 90 => m = 45 years.
Q25. A Man Rows To A Place 48 Km Distant And Come Back In 14 Hours. He Finds That He Can Row four Km With The Stream In The Same Time As three Km Against The Stream. The Rate Of The Stream Is ?
Suppose he flow four km downstream in x hours. Then,
Speed downstream =(four/x)km/hr
Speed up circulate =(3/x)km/hr
48/4/x+forty eight(three/x)=14 or x=half of
So,speed downstream = eight km/hr,velocity upstream =6km/hr
Rate of the circulate = half(eight-6)km/hr =1 km/hr.
Q26. The Sum Of The Digits Of A Two-digit Number Is
Let the 2-digit range be 10a + b
a + b = 12 --- (1)
If a>b, a - b = 6
If b>a, b - a = 6
If a - b = 6, adding it to equation (1), we get
2a = 18 => a =nine
so b = 12 - a = three
Number would be 93.
If b - a = 6, including it to the equation (1), we get
2b = 18 => b = 9
a = 12 - b = three.
Number would be 39.
Therefore, Number might be 39 or 93.
Q27. A Sells His Goods 50% Cheaper Than B But 50% Dearer Than C. The Cheapest Is ?
Let B = 100
A = 50
C * (150/one hundred) = 50
3C = one hundred
C = 33.Three then 'C' Cheapest
Q28. Ten Years Ago, The Age Of Anand Was One-1/3 The Age Of Bala At That Time. The Present Age Of Bala Is 12 Years More Than The Present Age Of Anand. Find The Present Age Of Anand ?
Let the present ages of Anand and Bala be 'a' and 'b' respectively.
A - 10 = 1/three (b - 10) --- (1)
b = a + 12
Substituting b = a + 12 in first equation,
a - 10 = 1/3 (a + 2) => 3a - 30 = a + 2
=> 2a = 32 => a = sixteen.