# Interview Questions.

Ibm Aptitude Placement Papers - Ibm Aptitude Interview Questions and Answers

## Ibm Aptitude Placement Papers - Ibm Aptitude Interview Questions and Answers

Q1. A Man Possesses 2/three Of The Statistical Surveying Bureau Business And Offers 3/four Of His Offers For Rs. 750

three/4 of his provide = 75000

So his offer = 100000.

2/three of enterprise esteem = a hundred thousand

So upload as much as esteem = 150000

Q2. 60 Liters Of Diesel Is Required To Movement six hundred Km Utilizing An 800 Cc Motor. In The Event That The Volume Of Diesel Required To Cover A Separation Changes Specifically As The Limit Of The Motor, At T

Let hold 800 cc consistent and compute the degree of diesel for 800 km

800*60/six hundred=eighty liters.

Presently, verify diesel required for brand spanking new separation i.E. 800 km,

80*1200/800=a hundred and twenty liters.

Q3. A Begins Riding His Bicycle At 10 Am With A Speed Of 20kmph And B Likewise Begins At 10 Am With A Speed Of 40kmph From A Similar Point In A Similar Way. Returns South At 12 O'clock And B Turns North A

At 12 O'clock, A cover 40km and on the other side B at eleven o clock cover 40km, again they went toward every other (that is actually the separation between them), this is A needs to make a journey 2hr (From 12 to two at 20km/hr.) i.E. 2*20=40km and opposite side B wishes to Travelled out 3hr (From eleven to 2 at 40km/hr.) i.E. 3*forty=120Km.

At that point Then the total distance traveled with the aid of them is the Actual distance among them i.E. 40+120= 160Km

Q4. What Annual Installment Will Discharge A Debt Of Rs. 4600 Due In four Years At 10% Simple Interest ?

Let the annual instalment be Rs. @The first instalment could be paid 365 days from now i.E. Three years before it is truly due. The second instalment can be paid two years from now i.E. 2 years earlier than it's far clearly due.

The third instalment may be paid 1 yr before it is sincerely due.

The fourth instalment may be paid on the day the amount is clearly due.

On the primary instalment the interest can be paid for 3 years, on the second for two years, on the 1/3 for 1 yr, at the fourth for 0 year. In general an hobby for six years may be paid (three + 2 + 1 + zero) on Rs. A hundred @ 10%. Interest = (100 × 6 × 10)/one hundred = Rs. 60 and the important is Rs a hundred × four = Rs four@The total mortgage that can be discharged is Rs. 400 + 60 = Rs. Forty six@Here the technique of Chain Rule could be applied. I.E. For Rs. 460 the instalment required is Rs. A hundred, for Rs. 4600 the instalment required is 4600 × a hundred/460 = Rs. A thousand.

Q5. A Is Twice As Fast As B Is Thrice As Fast As C. The Journey Covered By C In forty two Minutes, What Will Be Covered By A Is

B is three times as speedy as C

C blanketed in 42 mins

B protected in 42/3=14 min

A is two times as fast as B

A covers in 14*(1/2) = 7 min

Q6. If A Person Walks At 14 Km/hr Instead Of 10 Km/hr, He Would Have Walked 20 Km More. The Actual Distance Traveled By Him Is:

Let the actual separation voyaged be x km.

At that point, x/10 = (x + 20)/14.

=> 14x = 10x + 2 hundred

=> 4x = two hundred.

=> x = 50 km.

Q7. Gavaskar's Average In His Initial 50 Innings Was 5

Add up to attain after 50 innings = 50*50 = 2500

Total rating after fifty one innings = 51*fifty one = 2601.

So, runs made in the 51st innings = 2601-2500 = one hundred and one

If he had now not lost his wicket in his 51st innings, he could have scored an unbeaten 50 in his 51st innings.

Q8. A Man Pushes Downstream 30 Km And Upstream 18 Km, Taking five Hours Each Time. What Is The Speed Of The Stream (modern) ?

Let x=pace of boat and y=speed of modern-day

=30/ (x+y)=18/(x-y)=5 with the aid of fixing y=1.2 km/hr

Q9. Anirudh, Harish, And Sahil Put A Sum Of Rs.1, 35,000 In The Proportion 5:6:4 Anirudh Contributed Has The Capital For eight Months. Harish Contributed For A Half Year And Sahil Contributed For 4 Months. On

Anirudh contribute for 8 months, Harish contributed for 6 and

sahil for 4 months in the proportion of five:6:four

so share = 5*eight : 6*6 : four*4

=> 40:36:16

=> 10:9:4

So sahil's profit= (4/23)*75900 = 13200

Q10. A, B, C Are The Partner In A Business. During A Specific Year. A Got 33% Of The Benefit. B Got One-fourth Of The Benefit And C Got The Rest Of The Rs. 50

Lets anticipate Total benefit x

x * (1-1/three-1/4) = 5000

=> x*(12-four-three)/12 = 5000

x = 5000*12/5 = Rs. 12000

so An's offer = Rs. (1/3*12000) = Rs. 4000

Q11. In A Race Of 600 Metres, A Can Beat B By 60 Metres And In A Race Of 500 Metres, B Can Beat C By 50 Metres. By How Many Metres Will A Beat C In A Race Of 400 Metres ?

A runs B runs C runs

600 metres race 600m 540 m

500 metres race 500 m 450m

Combing ratio A runs B runs C runs

300metres - 2700meters - 2430metres

Unitary A runs B runs C runs

Method 400mtres - 360 metres - 324 metres

∴ A beats C by four hundred-324 = 76 metres.

Q12. A Man Purchases A Book For Rs.29.50 And Offers It For Rs 31.

So we've got C.P. = 29.50

S.P. = 31.10

Gain = 31.10 - 29.50 = Rs. 1.6

Gain %=( Gain/Cost*one hundred)%

= (1.6/29.50*one hundred)%=five.Four%

Q13. Nirmal And Kapil Began A Business Contributing Rs. 9000 And Rs. 12000 Separately. Following A Half Year, Kapil Pulled Back Portion Of His Speculation. In The Event That Following A Year, The Aggregate

Nirmal: Kapil = 9000*12:(12000*6+6000*6) = 1:1

Kapil share = Rs. [4600 *(half of)) = Rs. 2300

Q14. A Boat Can Go At A Speed Of thirteen Km/hr In Still Water. On The Off Chance That The Speed Of The Stream Is four Km/hr, Discover The Time Taken By The Vessel To Go 68 Km Downstream.

Speed downstream = (13 + 4) km/hr = 17 km/hr.

Time taken to movement 68 km downstream = (sixty eight/17) hrs = four hrs

Q15. Look At The Series: A4, __, C16, D32, E6

The letters Increase with the aid of 1; the numbers are duplicated by means of 2.

Q16. I Drove 60 Km At 30 Kmph And After That An Extra 60 Km At 50 Km Ph. Register My Normal Speed Over My 120 Km.

37 ½ km ph Solution: Time required for the initial 60 km = one hundred twenty min.

The Time required for the second 60 km = seventy two min.

Add as much as time required = 192 min

Average speed = (60*one hundred twenty)/192 = 37 half of

Q17. Teena Is More Youthful Than Rani By 6 Years. On The Off Chance That The Proportion Of Their Ages Is 6:eight, Discover The Time Of Teena:

On the off threat that Rani Age is x, at that factor Teena age is x-6,

So (x-6)/x = 6/8

=> 8x-forty eight = 6x

=> 2x = 48

=> x = 24

So, Teena age is 24-6 = 18 years

Q18. On The Off Chance That The Accumulated Dividends On A Specific Total Of Cash For A Long Time At 10% For Each Annum Be Rs. 993, What Might Be The Basic Intrigue?

Let P = Principal

A - Amount

We have a = P (1 + R/a hundred)3 and CI = A - P

ATQ 993 = P (1 + R/a hundred)three - P

∴ P = Rs 3000/ -

Presently SI @ 10% on Rs 3000/ - for three yrs = (3000 x 10 x three)/a hundred

= Rs 900/ -

Q19. In A Race Of six hundred Meters, A Can Beat B By 60 Meters And In A Race Of 500 Meters; B Can Beat C By 50 Meters. By What Number Of Meters Will A Beat C In A Race Of 400 Meters ?

Let's expect A finishes the six hundred m race in 60 sec, then

600/60 = 10 m/sec is his speed

B traveled (six hundred-60 = 540 m in 60 sec, therefore

540/60 = nine m/sec is B's pace

"in a race of 500 metres, B can beat C by using 50 metres."

500/9 = fifty five.56 sec is B's time to complete a 500 m race

C traveled 500-50 = 450 m in fifty five.56 sec, consequently

450/fifty five.Fifty six = 8.1 m/sec is C's velocity

By what number of will A beat C in a race of four hundred metres?

400/10 = forty sec for A to run a four hundred m race

C will travel 8.1*40 = 324 m in forty sec therefore

C might be 400-324 = seventy six m at the back of whilst A crosses the end line

Q20. A Train 125 Meter Long Is Running At 50 Km/hr. In What Time Will It Pass A Man Running At 5 Km/hr In A Similar Bearing In Which The Train Is Going ?

Distance=125 meter pace=50-5=45km/hr=>forty five*5/18=12.5 m/s

Time=a hundred twenty five/12.Five=10sec

Q21. If 20 Men Can Construct A Divider Of 112 Meters In Length In 6 Days, What Length Of A Comparable Divider Can Be Worked By 25 Men In three Days ?

20 men in 6 days can construct 112 meters

25 men in 30 days can construct=112*(25/20)*(three/6)

= 70 meters

Q22. A Number Whose Fifth Part Expanded By 5 Is Equivalent To Its Fourth Part Lessened By five, Is

X/5 + five = x/four - 5

⇒ x/five - x/four = 10

X/20 = 10

⇒ x = two hundred

Q23. A Can Complete A Work In forty Days And B In 28 Days. In The Event That A And B Together Take Every Necessary Step, At That Point Roughly In How Long Will A Similar Function Be Finished ?

A's 1day's paintings = 1/40

B's 1day's paintings = 1/28

They can cooperate in = 1/40 + 1/28 = 16 days (estimate)

Q24. What Is The Aggregate Of All Numbers Somewhere In The Range Of a hundred And a thousand Which Are Distinct By 14 ?

The number nearest to a hundred that's extra noteworthy than one hundred and divisible by way of 14 is 112, that's the primary term of the association which need to be summed. The wide variety nearest to a thousand that is beneath one thousand and awesome by means of 14 is 994, that is the last time period of the association. 112 + 126 + .... + 994 = 14(8+9+ ... + 71) = 35392

Q25. A Quick Typist Can Type Some Issue In 2 Hours And A Moderate Typist Can Type The Same In three Hours. In The Event That Both Kinds Consolidate, In What Amount Of Time Will They Wrap Up ?

The quick typist's paintings completed in 1 hr = half of

The slight typist's work performed in 1 hr = 1/three

If they paintings to enroll in, paintings is completed in 1 hr = half of+1/3 = 5/6 So,

the paintings may be finished in 6/five hours. I.E., 1+1/five hours = 1hr 12 min